First Part of an Elementary Treatise on Spherical Trigonometry |
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Page 66
We shall assume the surface of the hemisphere as this standard , and shall suppose it to be divided into 360 equal ( 867 ) parts , which we shall call degrees of surface . These degrees may be again subdivided into minutes and ( 868 ) ...
We shall assume the surface of the hemisphere as this standard , and shall suppose it to be divided into 360 equal ( 867 ) parts , which we shall call degrees of surface . These degrees may be again subdivided into minutes and ( 868 ) ...
Page 67
The lunary sursace AMNA ' ( 873 ) is therefore the same part of the hemisphere , which the angle A is of 180 ° , or which 2 A is of 360 ° , or the surface AMNA 2 A ; ( 874 ) surface of hemisphere 360 ° that is , 2 A is equal to the ...
The lunary sursace AMNA ' ( 873 ) is therefore the same part of the hemisphere , which the angle A is of 180 ° , or which 2 A is of 360 ° , or the surface AMNA 2 A ; ( 874 ) surface of hemisphere 360 ° that is , 2 A is equal to the ...
Page 70
The sum of ( 895 ) , ( 896 ) , and ( 897 ) , is 3 X the surface ABC + the surface A'BC ( 899 ) + the surface ABC " + the surface A'BC = 2 A + 2 B + 2 C. But the surface of the hemisphere is , by ...
The sum of ( 895 ) , ( 896 ) , and ( 897 ) , is 3 X the surface ABC + the surface A'BC ( 899 ) + the surface ABC " + the surface A'BC = 2 A + 2 B + 2 C. But the surface of the hemisphere is , by ...
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First Part of an Elementary Treatise on Spherical Trigonometry (Classic Reprint) Benjamin Peirce No preview available - 2017 |
First Part of an Elementary Treatise on Spherical Trigonometry Benjamin Peirce No preview available - 2016 |
Common terms and phrases
A'BC acute adjacent angles angles are given becomes calculated called Corollary corresponding cosec cosine cotan deduced Demonstration denote determined differs divided equal to 90 equation EXAMPLES expressions factor fall on AC Fourthly fractions given angle gives greater than 90 half the sum hemisphere Hence hypothenuse impossible included angle known leads legs Lemma less than 90 Let ABC fig let fall logarithm lunary surface measured middle negative numerator obtained obtuse opposite angle opposite side perpendicular perpendicular BP positive preceding Problem proportion proved quantity quotient reduce result right angle Rules satisfy Scholium second member Secondly sides and angles sides equal signs sine Solution solve a spherical solve the triangle spherical right triangle spherical triangle ABC substituted supplements surface ABC tang tangent of half Theorem Thirdly tive trian triangle ABC figs whence
Popular passages
Page 69 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Page 1 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Page 69 - THEOREM. The surface of a spherical triangle is measured by the excess of the sum of its three angles above two right angles, multiplied by the tri-rectangular triangle.
Page 8 - I. The sine of the middle part is equal to the product of the tangents of the adjacent parts.
Page 8 - II. The sine of the middle part is equal to the product of the cosines of the opposite parts.
Page 30 - Any angle is greater than the difference between 180° and the sum of the other two angles.
Page 51 - The cosine of half the sum of two sides of a spherical triangle is to the cosine of half their difference as the cotangent of half the included angle is to the tangent of half the sum of the other two angles.
Page 51 - The cosine of half the sum of two angles of a spherical triangle is to the cosine of half their difference as the tangent of half the included side is to the tangent of half the sum of the other two sides.
Page 71 - ... and the sum of the angles in all the triangles is evidently the same as that of all the angles of the polygon ; hence, the surface of the polygon is equal to the sum of all its angles, diminished by twice as many right angles as it has sides less two, into the tri-rectangular triangle.