Plane Geometry |
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Page 36
... hypothesis . 2. If two adjacent have their exterior sides in a st . line , they are supplementary . 3. By hypothesis . 4. Reason 2 above . 5. Supplements of the same angle are equal . Beside each statement is the reason for its ...
... hypothesis . 2. If two adjacent have their exterior sides in a st . line , they are supplementary . 3. By hypothesis . 4. Reason 2 above . 5. Supplements of the same angle are equal . Beside each statement is the reason for its ...
Page 88
... Hypothesis . In AABC and ADEF : ZC and DFE are rt . 4 ; AB DE ; BC = EF . = Conclusion . AABC Plan . Try to prove ZA ... hypothesis . 2. Hypothesis . 3. Why ? by 4. Post . 18 , p . 31 . 5. § 42 , p . 43 . 6. Step 1 . 7. Hypothesis ...
... Hypothesis . In AABC and ADEF : ZC and DFE are rt . 4 ; AB DE ; BC = EF . = Conclusion . AABC Plan . Try to prove ZA ... hypothesis . 2. Hypothesis . 3. Why ? by 4. Post . 18 , p . 31 . 5. § 42 , p . 43 . 6. Step 1 . 7. Hypothesis ...
Page 90
... hypothesis and conclusion . ( a ) If the theorem is stated in the if - then form , the hypothesis and conclusion are evident at once . ( b ) If the theorem is not in the if - then form , the sub- ject of the sentence with its modifiers ...
... hypothesis and conclusion . ( a ) If the theorem is stated in the if - then form , the hypothesis and conclusion are evident at once . ( b ) If the theorem is not in the if - then form , the sub- ject of the sentence with its modifiers ...
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Common terms and phrases
AABC ABCD ADDITIONAL EXERCISES ADEF adjoining figure altitude angle formed angles are equal apothem ARST AXYZ base angles bisector bisects central angle chord circumscribed conclusion corresponding sides cuts diagonals diameter Draw drawn equal angles equal circles equal sides equidistant equilateral triangle EXERCISES FOR CHAPTER extended exterior angle figure for Ex Find the area geometry hypotenuse Hypothesis inscribed inscribed angle intersect isosceles trapezoid isosceles triangle Locate locus of points mean proportional measure median meeting AC mid-point opposite sides parallelogram perimeter perpendicular perpendicular-bisector Plan plane Proof Prove pupil quadrilateral radii radius ratio rectangle regular hexagon regular polygon rhombus right angle right triangle secant similar triangles square STATEMENTS REASONS straight line Suggestion tangent theorem vertex angle vertices XYZW ZAOB