Plane Geometry |
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Page 58
... ADEF : AB DE ; AC Hypothesis . = DE ; AC = DF ; and BC = EF . Conclusion . AABC ADEF . Plan . First prove ACB = ≤F ; then use s.a.s. = s.a.s. Proof : STATEMENTS 1. Place ADEF with D on A , DE on AB , and F at G , on the opposite side ...
... ADEF : AB DE ; AC Hypothesis . = DE ; AC = DF ; and BC = EF . Conclusion . AABC ADEF . Plan . First prove ACB = ≤F ; then use s.a.s. = s.a.s. Proof : STATEMENTS 1. Place ADEF with D on A , DE on AB , and F at G , on the opposite side ...
Page 88
... ADEF . ZD ; then use § 99 . STATEMENTS 1. Place AABC so that BC coincides with EF , B on E , C on F , and A falls at ... ADEF : AB DE ; 22 = 21 ; = ZA = LD . .. AABC ADEF . REASONS 1. Post . 22 , p . 44 . BC EF , = hypothesis . 2 ...
... ADEF . ZD ; then use § 99 . STATEMENTS 1. Place AABC so that BC coincides with EF , B on E , C on F , and A falls at ... ADEF : AB DE ; 22 = 21 ; = ZA = LD . .. AABC ADEF . REASONS 1. Post . 22 , p . 44 . BC EF , = hypothesis . 2 ...
Page 203
... ADEF : AB AC BC = DE DF AABC = EF ADEF . F Plan . On AABC , construct a triangle that can be proved similar to AABC and congruent to ADEF . Proof : STATEMENTS 1. On AB , take AX DE . On AC take = AY DF . Draw XY . = AB AC 2 . = DE DF AB ...
... ADEF : AB AC BC = DE DF AABC = EF ADEF . F Plan . On AABC , construct a triangle that can be proved similar to AABC and congruent to ADEF . Proof : STATEMENTS 1. On AB , take AX DE . On AC take = AY DF . Draw XY . = AB AC 2 . = DE DF AB ...
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Common terms and phrases
AABC ABCD ADDITIONAL EXERCISES ADEF adjoining figure altitude angle formed angles are equal apothem ARST AXYZ base angles bisector bisects central angle chord circumscribed conclusion corresponding sides cuts diagonals diameter Draw drawn equal angles equal circles equal sides equidistant equilateral triangle EXERCISES FOR CHAPTER extended exterior angle figure for Ex Find the area geometry hypotenuse Hypothesis inscribed inscribed angle intersect isosceles trapezoid isosceles triangle Locate locus of points mean proportional measure median meeting AC mid-point opposite sides parallelogram perimeter perpendicular perpendicular-bisector Plan plane Proof Prove pupil quadrilateral radii radius ratio rectangle regular hexagon regular polygon rhombus right angle right triangle secant similar triangles square STATEMENTS REASONS straight line Suggestion tangent theorem vertex angle vertices XYZW ZAOB