 O F' it also bisects the angle formed by the lines AC and E F. PROBLEM 10. To Divide a Given Line into any Number of Equal Parts. Let AC, about 3^ inches long, be the given line. Let us divide it into 7 equal parts. Draw the line AJ at least 4 inches...  Mechanical drawing - Page 22by American School (Chicago, Ill.) - 1903Full view - About this book
 | Robert Griffith Hatfield - Architecture - 1845 - 326 pages
...will be the line required. This is upon the same principle as Art. 76. a I e is A • Fig. 37 80. — To divide a given line into any number of equal parts. Let ab, (Fig. 37,) be the given line, and 5 the number of parts. Draw ac, at any angle to ab • on ac,... | |
 | Nathaniel Bowditch - 1846 - 854 pages
...bisections any number of times. This problem is useful in constructing the mariner's compass. PROBLEM XL To divide a given line into any number of equal parts. Let it be required to .divide the line AB into five equal parts. From the point A dray any line, AD, making... | |
 | Robert Scott Burn - Architectural drawing - 1853 - 102 pages
...с, е above and below the line, through these draw a line с de ; dis the " point of bisection."* 3 To DIVIDE A GIVEN LINE INTO ANY NUMBER < OF EQUAL PARTS. — Let a 6, fig. 59, be the line ; from a and b, with ab, describe arcs ac, bd ; from ab, with any distance... | |
 | Horatio Nelson Robinson - History - 1853 - 334 pages
...make the same angle with AB; they are, therefore, parallel. (Definition of parallel lines). PROBLEM 7. To divide a given line into any number of equal parts. Let AB represent the given line, and let it be required to divide it into any number of equal parts, say... | |
 | Horatio Nelson Robinson - Conic sections - 1854 - 350 pages
...make the same angle with AB; they are, therefore, parallel. (Definition of parallel lines). PROBLEM 7. To divide a given line into any number of equal parts. Let AB represent the given line, and let it be required to divide it into any number of equal parts, say... | |
 | Horatio Nelson Robinson - Geometry - 1860 - 470 pages
...BC make the same angle with AC, they are, therefore, parallel, (B. I, Th. 7, Cor. 1). PROBLEM VII. To divide a given line into any number of equal parts. Let AB represent the given line, and let it be required to divide it into any number of equal parts, say... | |
 | Horatio Nelson Robinson - Geometry - 1868 - 276 pages
...BC make the same angle with AC, they are, therefore, parallel, (B. I, Th. 7, Cor. 1). PROBLEM VII. To divide a given line into any number of equal parts. Let AB represent the given line, uud let it be required to divide it into any number of equal parts, say... | |
 | Edward Brooks - Geometry - 1868 - 284 pages
...CAP is a right angle (B. IV. Th. VII. C. 1); hence, AP is a tangent (B. IV. Th. IV.). PROBLEM XIII. To divide a given line into any number of equal parts. Let AB be the given line, and suppose we wish to divide it into any number, say 5 equal parts. Through... | |
 | Robert Griffith Hatfield - Architecture - 1874 - 452 pages
...line, ea ; which will be the line required. This is upon the same principle as Art. 76. Fig. 37 80. — To divide a given line into any number of equal parts. Let ab, (Fig. 37,) be the given line, and 5 the number of parts. Draw ac, at any angle to ab ; on ac, from... | |
 | William Guy Peck - Conic sections - 1876 - 376 pages
...direction of the chord. APPLICATION OF PRECEDING PRINCIPLES TO THE CONSTRUCTION OF PROBLEMS. PROBLEM I. To divide a given line into any number of equal parts. Let it be required to divide AE into three equal parts. From A draw any other line, and on it lay off AK,... | |
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