 | Thomas Sherwin - Algebra - 1841 - 314 pages
...second term of the root, also at the right of the divisor. Multiply the divisor, with the term annexed, by the second term of the root, and subtract the product from the dividend. 4. The remainder will form a new dividend, which is to be divided by twice the whole root... | |
 | William Scott - Algebra - 1844 - 568 pages
...term of the root. Multiply the algebraic sum of double the first and once the second term of the root by the second term of the root, and subtract the product from the first remainder ; divide the first term of the second remainder by double the first term of the root;... | |
 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...of the root, by the second term, plus the square of the second term. Multiply the complete divisor by the second term of the root, and subtract the product from the remainder, and bring down the next remainder. Divide the first term of this remainder by three times... | |
 | Charles William Hackley - Algebra - 1846 - 544 pages
...second term of the root), with its proper sign, to the divisor. 5°. Multiply the whole of this divisor by the second term of the root, and subtract the product from the first remainder. 6°. Divide this second remainder by twice the sum of the first two terms of the root... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...found, and annex the result both to the root and the divisor. Multiply the divisor thus increased, by the second term of the root, and subtract the product from the remainder. 3d. Double the terms of the root already found, for a partial divvsor, and divide the first... | |
 | Joseph Ray - Algebra - 1852 - 408 pages
...three times the product of the first term by the second, plus the square of the second. Multiply these by the second term of the root and subtract the product from the first remainder. 3rd. Again find how often the trial divisor is contained in the first term of the... | |
 | Thomas Sherwin - Algebra - 1855 - 262 pages
...second term of the root, also at the right of the divisor. Multiply the divisor, with the term annexed, by the second term of the root, and subtract the product from the dividend. 4. The remainder will form a second dividend, which is to be divided by twice the whole root... | |
 | Theodore Strong - Algebra - 1859 - 570 pages
...the incomplete divisor, and the result will be the complete divisor. Multiply the complete divisor by the second term of the root, and subtract the product from the first remainder, cutid the result will constitute the second remainder. 3. Take twice the root now... | |
 | Ebenezer Bailey - Algebra - 1860 - 264 pages
...sign, both to the root and to the right of the divisor. (4.) Multiply the divisor thus increased bу the second term of the root, and subtract the product from the dividend ¡ the remainder will form a new dividend. (5.) Double the whole root for a new divisor, and... | |
 | Thomas Sherwin - 1862 - 252 pages
...second term of the root, also at the right of the divisor. Multiply the divisor, with the term annexed, by the second term of the root, and subtract the product from the dividend. 4. The remainder will form a second dividend, which is to be divided by twice the whole root... | |
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Multiply the divisor thus increased, by the second term of the root, and subtract the product from the remainder. 
