 | Jeremiah Day - Logarithms - 1815 - 172 pages
...one third of the arithmetical complement of the logarithmic cosine. The remainder diminished by 10, will be the logarithm of the number of seconds in the arc. To find a small arc from its logarithmic SINE. From the sum of the constant quantity 5.3144251, and... | |
 | Jeremiah Day - Geometry - 1824 - 440 pages
...one third of the arithmetical complement of the logarithmic cosine. The remainder diminished by 10, will be the logarithm of the number of seconds in the arc. Tojind a small arc from its logarithmic TANGENT. From the sum of the constant quantity 5.3144251, and... | |
 | Dionysius Lardner - Plane trigonometry - 1828 - 434 pages
...From the logarithm of the number of square feet in the area subtract the constant number 9.3267737, and the remainder will be the logarithm of the number of seconds in the spherical excess." (298.) In this method of computing the spherical excess, it is necessary that the... | |
 | Jeremiah Day - Measurement - 1831 - 520 pages
...two thirds of the arithmetical complement of the logarithmic cosine. The remainder diminished by 10, will be the logarithm of the number of seconds in the arc. A TABLE OF NATURAL SINES AND TANGENTS; TO EVERT TEN MINUTES OF A DEGREE. IF the given angle is less... | |
 | Jeremiah Day - Measurement - 1831 - 394 pages
...one third of the arithmetical complement of the logarithmic cosine. The remainder diminished by 10, will be the logarithm of the number of seconds in the arc. Tofind a small arc from its logarithmic TANGENT. From the sum of the constant quantity 5.3144251, and... | |
 | Jeremiah Day - Logarithms - 1831 - 418 pages
...two thirds of the arithmetical complement of the logarithmic cosine. The remainder diminished by 10, will be the logarithm of the number of seconds in the arc. From the sum of the constant quantity 5.3144251, and the For the demonstration of these rules, see... | |
 | Charles Hutton - Logarithms - 1834 - 466 pages
...the arc from, the sine. To the given log. sine of a small arc 5-3144251, add ^ of arith. сотр. of the log. cosine: subtract 10 from the index of the sum, the remainder will be the log. of the number of seconds and decimals in the arc sought. 4. To find... | |
 | Jeremiah Day - Measurement - 1836 - 418 pages
...two thirds of the arithmetical complement of the logarithmic cosine. The remainder diminished by 10, will be the logarithm of the number of seconds in the arc. A TABLE OF NATURAL SINES AND TANGENTS; TO EVERY TEN MINUTES OF A DEGREE. IF the given angle is less... | |
 | Charles William Hackley - Trigonometry - 1838 - 328 pages
...the arc from the log. sine the rule is this. T*o the log. sine of the small arc add 5.314425, and | of the arithmetical complement of the log. cosine...then from the expression (3), last problem, we have 28 log. n=log.tan x—4,685575—2 ar ithx;omp.log.cosr. =log.tan x + 5.314425—10—jarith.comp.... | |
 | Charles William Hackley - Trigonometry - 1838 - 338 pages
...the arc from the log. sine the rule is this. To the log. sine of the small arc add 5.314425, and f of the arithmetical complement of the log. cosine...arc. 2. Let the log. tangent be given ; then from the expres* sion (3), last problem, we have L log. n=log.lan x—4.685575—*arith.comp.log.cos:r. =log.tan... | |
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of the arithmetical complement of the log. cosine; subtract 10 from the index of the sum, and the remainder will be the logarithm of the number of seconds in the arc. 2. Let the log. tangent be given; then from the expression (3), last problem, we have 
