| Thomas Keith - 1817 - 306 pages
...2 feet 1 inch 10 parts 6 seconds. PROBLEM III. To find the Area of a PJtombus, or of a Rhomboidcs. RULE. Multiply the length by the perpendicular breadth, and the product will be the area *. Perpend. . * DaMMnMMI. Benuse parallelograms upon the same base and between the same parallels arc... | |
| William Jillard Hort - 1822 - 308 pages
...the area of a parallelogram, whether it be a square, a rectangle, a rhombus, or a rhomboid. Rule 1. Multiply the length by the perpendicular breadth, and the product will be the area. a. As the radius is to the sine of any angle of the parallelogram- vn is tlip prnAn^t of the sirle»... | |
| Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...Sq.Acre. 100,000 160 10 4 I Sq. Mile. 64,000,000 102,400 6,400 2,560 640 1 PROBLEM 1. To find the Area of a Parallelogram. RULE. Multiply the length by the...perpendicular breadth, and the product will be the area. Note. — The above rule is true, whether the figure be a square, rhombus, or a rhomboid. EXAMPLE.... | |
| Ireland commissioners of nat. educ - 1834 - 370 pages
...breadth 28 feet 9 inches ? Ans. 1164 feet 4 inches 6 parts PROBLEM III. To find the area of a Rhombus. RULE. Multiply the length by the perpendicular breadth, and the product will be the area.* 1 . What is the area of a rhombus, whose side is 16 feet, and perpendicular breadth 10 feet ? Ans.... | |
| Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...1164 feet 4 inches, 6 parts. MENSURATION OF SUPERFICIES. PROBLEM III. To find the area of a Rhombus. RULE. Multiply the length by the perpendicular breadth, and the product will be the area.* 1. What is the area of a rhombus, whose side is 16 feet, and perpendicular breadth 10 feet ? Ans. 16... | |
| Commissioners of National Education in Ireland - Measurement - 1841 - 286 pages
...Ans. 1164 feet 4 inches 6 parts. PROBLEM III. To find the area of a rhombus. RULE. Multiply the j^ length by the perpendicular breadth, and the product will be the area.* 1. What is the area of a rhombus, whose side is 16 feet, and perpendicular breadth 10 feet? Ans. 16... | |
| Horatio Nelson Robinson - Navigation - 1858 - 356 pages
...they contain. The unit may be taken at pleasure ; it may be an inch, foot, yard, rod, mile, ifec., as convenience and propriety may dictate. The square...Multiply the length by the perpendicular breadth, and tht product will be the area. (Leg. b. IT, prop. V. Rob. book I, th. 29). 1. What is the area of a... | |
| A. C. Smeaton - Building - 1867 - 314 pages
...are some others which are worthy of notice. PROBLEM III. To find the Area of a Rhombus or Rhomboides. RULE. Multiply the length by the perpendicular breadth, and the product will be the area. Let the side of a rhombus be 17 feet, and the perpendicular 15 feet, what is its area ? 17 X 15 =255,... | |
| John Barter (of the science and art coll, Plymouth.) - 1877 - 328 pages
...measures 3 ft. 1 in. at 12s. 6d. per cubic foot. EXERCISE CCXIII. To find the area of a rhombus, AB c D. Rule. — Multiply the length by the perpendicular breadth, and the product will be the area. Example.— Let AB or D c = 18 ft. and AE = 10 ft., then 18x10 = 180 sq. ft. area. 1. What is the contents... | |
| Frederick Thomas Hodgson - Carpentry - 1883 - 168 pages
...Rhomboides. Rule. — Multiply the base by the perpendicular height and half the product will be the area. Multiply the length by the perpendicular breadth, and the product will be the area. Let the side be 17 feet, and the perpendicular 15 feet, then 17 X 15 =255, the area required. To Find... | |
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