The Elements of Euclid for the Use of Schools and Colleges: Comprising the First Six Books and Portions of the Eleventh and Twelfth Books : with Notes, an Appendix, and Exercises |
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Page 273
... middle point of the straight line AB ; then it may be shewn that this straight line is at right angles to AB ; and therefore the centre of the circle must lie in this straight line , by III . 1 , Corollary . In the same manner it may be ...
... middle point of the straight line AB ; then it may be shewn that this straight line is at right angles to AB ; and therefore the centre of the circle must lie in this straight line , by III . 1 , Corollary . In the same manner it may be ...
Page 293
... middle point of the base . Let ABC be a triangle ; and let D be the middle point of the base AB . Draw CE perpendicular to the base A A A meeting it at E ; then E may be either in AB or in AB produced . First , let E coincide with D ...
... middle point of the base . Let ABC be a triangle ; and let D be the middle point of the base AB . Draw CE perpendicular to the base A A A meeting it at E ; then E may be either in AB or in AB produced . First , let E coincide with D ...
Page 311
... middle point of AB we can shew that this straight line is at right angles to AB : that is , the line which bisects AB at right angles passes through G. 25. The straight lines drawn from the angles of a triangle to the points of ...
... middle point of AB we can shew that this straight line is at right angles to AB : that is , the line which bisects AB at right angles passes through G. 25. The straight lines drawn from the angles of a triangle to the points of ...
Page 315
... middle points of OA , OB , OC respectively ; let G be the foot of the perpendicular from A on BC , and H the middle point of BC . H Then OBG is a right - angled triangle and E is the middle point of the hypotenuse OB ; therefore EG is ...
... middle points of OA , OB , OC respectively ; let G be the foot of the perpendicular from A on BC , and H the middle point of BC . H Then OBG is a right - angled triangle and E is the middle point of the hypotenuse OB ; therefore EG is ...
Page 316
... centre of the Nine points circle and also bisect SO . Hence the centre of the Nine points circle must coincide with the middle point of SO . We may state that the Nine points circle of any triangle touches the inscribed circle and the ...
... centre of the Nine points circle and also bisect SO . Hence the centre of the Nine points circle must coincide with the middle point of SO . We may state that the Nine points circle of any triangle touches the inscribed circle and the ...
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Common terms and phrases
ABCD angle ABC angle ACB angle BAC angle EDF angles equal Axiom base BC BC is equal bisects the angle centre chord circle ABC circle described circumference Construction Corollary describe a circle diameter double draw a straight equal angles equal to F equiangular equilateral equimultiples Euclid Euclid's Elements exterior angle given circle given point given straight line gnomon Hypothesis inscribed intersect isosceles triangle less Let ABC magnitudes middle point multiple opposite angles opposite sides parallelogram perpendicular plane polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION quadrilateral radius rectangle contained rectilineal figure remaining angle rhombus right angles right-angled triangle segment shew shewn side BC square on AC straight line &c straight line drawn tangent THEOREM touches the circle triangle ABC triangle DEF twice the rectangle vertex Wherefore
Popular passages
Page 286 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 30 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Page 34 - IF a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another; and the exterior angle equal to the interior and opposite upon the same side; and likewise the two interior angles upon the same side together equal to two right angles...
Page 37 - If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are together equal to two right angles.
Page 12 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Page 302 - Describe a circle which shall pass through a given point and touch a given straight line and a given circle.
Page 220 - If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.
Page 354 - Prove that the square on any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square on a side of the triangle by the rectangle contained by the segments of the base : and conversely.
Page 104 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Page 96 - The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles.