## A Course of Mathematics: In Two Volumes. For the Use of the Royal Military Academy, Volume 1 |

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Page vii

8 8 another proof of Multiplication 9 9 expansion by synthetic diDivision 13 13 vision 131 168 Reduction 18 17 Problems on these rules 131 131 Tables of weights and

8 8 another proof of Multiplication 9 9 expansion by synthetic diDivision 13 13 vision 131 168 Reduction 18 17 Problems on these rules 131 131 Tables of weights and

**measures**18 18 Greatest common**measure**... 132 Comparison of French and ... Page viii

234 To

234 To

**measure**an angle by the com- 402 Indeterminate Co - efficients 236 238 passes only ..... 402 Piling of balls .... 240 158 To find the diameter of a sphere triangular pile .. 240 158 Field problems ........ 403 square pile 240 159 ... Page 18

This is chiefly concerned in reducing money , weights , and

This is chiefly concerned in reducing money , weights , and

**measures**. ... Division I. SOLIDITY 18 ARITHMETIC . Problems on these rules 131 Tables of weights and**measures**18 18 Greatest common**measure**132. Page 20

WEIGHTS AND

WEIGHTS AND

**MEASURES**, Agreeubly to the Act of Uniformity , which took effect 1st January , 1826 . The term**MEASURE**is the most comprehensive of the two , and it is distinguished into six kinds , viz . :1. Length . 2. Surface . 3. Page 21

Imperial

Imperial

**Measure**of CAPACITY for all liquids , and for all dry goods , except such as are comprised in the third Division . 4 Gills 1 Pint 34.65925 2 Pints 1 Quart 69.3185 4 Quarts = 1 Gallon 277.274 Cubic Inches . 2 Gall .### What people are saying - Write a review

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A Course of Mathematics: Composed for the Use of the Royal Military Academy Charles Hutton No preview available - 2015 |

### Common terms and phrases

added algebraic angle answer applied arithmetical base called centre circle coefficients common compound contained continued cube decimal denominator denote describe diameter difference distance divided division divisor double draw drawn equal equation EXAMPLES expression extremes factors figure former four fraction functions give given greater half hence interest intersection join latter length less manner means measure meeting method Multiply obtained operation opposite parallel parallelogram perpendicular plane position principal PROBLEM proportional quantity question quotient radius ratio rectangle Reduce remainder respectively result right angles root rule sides signs simple solution square subtract successive supposing taken THEOREM third triangle Whence whole yards