 To obtain stress in GF, pass a section cutting GF, EF and GC, and take moments of the external forces to the right of the section, about point C as a center GF = + (R(h -d) + Hd]/(h - d) (S) To obtain stress in HG, pass a section cutting HG, HE...  Applied Mechanics and Strength of Materials - Page 191by Percy F. Benedict - 1922 - 270 pagesFull view - About this book
 | Milo Smith Ketchum - Building, Iron and steel - 1903 - 392 pages
...stresse.E E' and H /-, = o. To obtain stress in GD, pass section cutting // G, ll E' and GD, and take moments of the external forces to the left of the section about point // as a center. GD= H'1. — = + V sec e (48) (h— (f) sine To obtain stress in GF, pass a section... | |
 | Milo Smith Ketchum - Building, Iron and steel - 1904 - 398 pages
...center. = ^— h—d (49) To obtain stress in HG, pass a section .cutting HG, H E' and GD, and take moments of the external forces to the left of the section about the point D as a center. The stress in the windward post, AF, is zero above and V below the foot of the... | |
 | Albert Henry Heller - Strains and stresses - 1905 - 188 pages
...and 6 with R and y-, we have = Or jR«5 = Hi/?, 2/5 «5 Hence U2d = HyR. Thus we get a value for the sum of the moments of the external forces to the left of any section by scaling an ordinate between two strings, for 0 may be so chosen that H is some convenient... | |
 | William Richard King - Mechanical engineering - 1906 - 428 pages
...measures, as already shown, the bending moment at the section to a given scale, and is equal to the algebraic sum of the moments of the external forces to the left of the section. The depth of the shear diagram beneath any section shows, to a given scale, the shear at the section,... | |
 | Milo Smith Ketchum - Bridges - 1908 - 596 pages
...GF=+[R(h—<!)+Hd]/(k—d) (53) To obtain stress in HG, pass a section cutting HG, HE' and GD, and take moments of the external forces to the left of the section, about the point D as a center. H~G = — Hd/(h — d} (54) The stress in the windward post, A—F, is zero above... | |
 | David Albert Molitor - Structural analysis (Engineering) - 1910 - 400 pages
...parallel and the diagonal pq is cut bv a section Ft'. The lever arm for pq would be infinite. Since the sum of the moments of the external forces to the left of the section and of the three members cut must be zero, therefore the sum of the vertical components of these forces... | |
 | Albert Henry Heller - Strains and stresses - 1916 - 408 pages
...and 6 and strings 2 and 6 with K and i/5, we have Hence U.,d — Hyr,. Thus we get a value for the sum of the moments of the external forces to the left of any section by scaling an ordinate be-' tween two strings, for 0 may be so chosen that 77 is some convenient... | |
 | Milo Smith Ketchum - Bridges - 1920 - 592 pages
...(R(h -d) + Hd]/(h - d) (S) To obtain stress in HG, pass a section cutting HG, HE' and GD, and take moments of the external forces to the left of the section, about the point D as a center. HG = - H -d/(h - d') (6) The stress in the windward post, AF, is zero above and... | |
 | Milo Smith Ketchum - Bridges - 1920 - 582 pages
...stresses EE' and HE' = o. To obtain stress in G—D, pass section cutting HG, H—E' and G—D, and take moments of the external forces to the left of the section, about point H as a center. GD =Hh/[(hd) sine] = + V-secB (4) To obtain stress in GF, pass a section cutting... | |
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