Applied Mechanics and Strength of Materials1922 - Mechanics, Applied - 270 pages |
Common terms and phrases
angle angular acceleration axes beam bending body center of gravity center of percussion clockwise component compression computed considered cord cross section curve cylinder deflection diam direction distance distributed load elastic limit equal equation equilibrium Example external forces F₂ fibre stress fixed force F forces acting friction gear given horizontal inch inertia instantaneous intersection joint length line of action linear velocity magnitude minus moment of inertia motion neutral axis particle perpendicular plane plate point of application Prob problems produce product of inertia pulley radius of gyration reactions rectangular Refer to Fig represent resultant revolving rivets rotation shaft shear diagram shown in Fig side slope solve space diagram steel STRENGTH OF MATERIALS string polygon supported system of forces tangent tion triangle unit stress vector diagram velocity of point vertical W₂ weight zero
Popular passages
Page 12 - Every body continues in its state of rest or of uniform motion in a straight line, except in so far as it may be compelled by impressed forces to change that state.
Page 12 - III. To every action there is always an equal reaction; or, the mutual actions of two bodies are always equal and oppositely directed.
Page 94 - The moment with respect to an axis in a plane perpendicular to the force is equal to the product of the force times the perpendicular distance from the force to the axis.
Page 53 - For example, in geometry it is proved that the square on the hypotenuse of a right triangle equals the sum of the squares on the other two sides, and that the circumference of a circle- equals 3.1416 times the diameter.
Page 132 - An epicycloid is a plane curve generated by a point in the circumference of a circle which rolls upon another circle with which it is tangent externally.
Page 184 - For rivets under computed stress, the distance from the center of the rivet to the edge of the plate...
Page 191 - To obtain stress in GF, pass a section cutting GF, EF and GC, and take moments of the external forces to the right of the section, about point C as a center GF = + (R(h -d) + Hd]/(h - d) (S) To obtain stress in HG, pass a section cutting HG, HE...
Page 193 - ... (1,000 pounds) and the load (including weight) on the part of the beam to the left of the section (400 pounds). The arm of the reaction is 2 feet and that of the 400-pound force is 1 foot (the distance from the middle of the 400-pound load to the section). Hence M2= + 1,000 X 2-400 X 1= + 1,600 foot-pounds.
Page 6 - Introduction to Involute Spur Gears. In considering two curved surfaces in direct contact, it has been shown that the angular velocity ratio is inversely proportional to the segments into which the line of centers is cut by the line of action or common normal to the two surfaces in contact. If the line of action always intersects the line of centers at a fixed point, then the angular velocity ratio remains constant. This is the condition that is desired when two gear teeth mesh together : the angular...
Page 79 - Find the tension in the rope and the magnitude and direction of the reaction at the hinge.