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" Any exterior angle of a triangle is equal to the sum of the two opposite interior angles. "
Principles of Plane Geometry - Page 14
by James Wallace MacDonald - 1889 - 63 pages
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An Introduction to Geometry and the Science of Form: Prepared from the Most ...

Anna Cabot Lowell - Geometry - 1846 - 206 pages
...third angle of the other. 134. The exterior angle of a triangle, that is, the angve made by producing one of the sides of a triangle, is equal to the sum of the two opposite interior angles, (fig. 88.) Angle ACD = angle ABC + angle CAB. Dem. ACD + ACB = 2 RA; ABC + CAB -f ACB = 2 RA; therefore...
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Elements of Geometry, Theoretical and Practical: Containing a Full ...

George Clinton Whitlock - Mathematics - 1848 - 340 pages
...of a Right angled Triangle is equal to a right angle Cor. 8. The external angle formed by producing one of the sides of a triangle, is equal to the sum of the two opposite internal angles. Let a, b, c, be the three angles of any tri- /&, angle, and c adjacent to the external...
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Elemento of Geometry, Theoretical and Practical: Containing a Full ...

George Clinton Whitlock - Mathematics - 1848 - 338 pages
...(93) Triangle is equal to a right angle Cor. 8. The external angle formed by producing one of (94) the sides of a triangle, is equal to the sum of the two opposite internal angles. Let a, b, c, be the three angles of any triangle, and с adjacent to the external...
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Plane and Solid Geometry: To which is Added Plane and Spherical Trigonometry ...

George Roberts Perkins - Geometry - 1856 - 460 pages
...than the remaining angle ACB of the triangle ACB. THEOREM vI. The exterior angle, formed ly producing one of the sides of a triangle, is equal to the sum of the two interior and opposite aaigles of the triangle. In the. triangle ABC, if the side AB be produced...
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Plane and Solid Geometry: To which is Added Plane and Spherical Trigonometry ...

George Roberts Perkins - Geometry - 1860 - 472 pages
...than the remaining angle ACB of the triangle ACB. THEOREM VI. The exterior angle, formed by producing one of the sides of a triangle, is equal to the sum of the two interior and opposite angles of the triangle. In the triangle ABC, if the side AB be produced...
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Report of the Superintendent of Public Instruction

Michigan. Department of Public Instruction - Education - 1893 - 564 pages
...simplest manner you can conceive. GEOMETRY. Demonstrate the following propositions: 1. Any exterior angle of a triangle is equal to the sum of the two opposite interior angles. 2. If the squares of the sides of a quadrilateral are together equivalent to the squares of the diagonals,...
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Graded Course of Instruction for the Public Schools of Chicago

Chicago (Ill.). Board of Education - Elementary schools - 1872 - 130 pages
...a=db=ec=c d-{-e+c=a + b + c, or a flat angle, or two right angles. THEOREM II.—The exterior angle of a triangle is equal to the sum of the two opposite interior angles. g + d= 2 right angles. c+d+e=^2 right angles. g+d=c+d+c. In the following figures, mark and name angles....
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Elements of Plane and Solid Geometry

George Albert Wentworth - Geometry - 1877 - 416 pages
...right angles, or two thirds of one right angle. PROPOSITION XXII. THEOREM. 105. The exterior angle of a triangle is equal to the sum of the two opposite interior angles. B 6' Let ECU "be an exterior angle of the triangle ABC. We are to prove Z BCH = ZA + Z B. Z BCH+ Z...
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A Geometry for Beginners

George Anthony Hill - Geometry - 1880 - 348 pages
...53) ? Therefore, m = a -\- c (Axiom I.). That is, — Theorem. — An exterior angle of Fiff- **• a triangle is equal to the sum of the two opposite interior angles. Exercises.- — 1. Find the exterior angle of a triangle if the opposite interior angles are 38° 35'...
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Elements of Geometry

George Albert Wentworth - Geometry, Modern - 1881 - 266 pages
...right angles, or two thirds of one right angle. PROPOSITION XXII. THEOREM. 105. The exterior angle of a triangle is equal to the sum of the two opposite interior angles. л— — Let BC H be an exterior angle of the triangle ABC. We are to prove ZB СH = ZA + Z B. ZB...
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