In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of « in that term, and dividing by the number of the preceding term. The boys' algebra - Page 164by James Cahill (of Dublin.) - 1875 - 209 pagesFull view - About this book
| James Wood - Algebra - 1815 - 338 pages
...beginning from 0, is increased by unity, in every succeeding term. Also, the coefficient of each term is found by multiplying the coefficient of the preceding...term by the index of x in that term, and dividing by the index of a increased by unity. * 2 6.5.4.3 , . 6.5.4.3.2 6.5.4.3.2.1 + 1 5 aV + 20 a3^ + 1 5... | |
| Andrew Bell (writer on mathematics.) - 1839 - 500 pages
...(m — n — 1 ), and dividing it by и ; therefore, generally. (484.) ' The coefficient of any term is found by multiplying the coefficient of the preceding term by the exponent of the leading quantity in that term, and dividing by the number denoting the place of the... | |
| Meteorology - 1842 - 886 pages
...co-efficient of a term involving a letter affected with an exponent one less than in a preceding term is found by multiplying the co-efficient of the preceding term by the greater exponent. I have demonstrated the truth of these rules for the powers of any letter united... | |
| 1842 - 934 pages
...co-efficient of a term involving a letter affected with an exponent one less than in a preceding' term is found by multiplying the co-efficient of the preceding term by the greater exponent. I have demonstrated the truth of these rules for the powers of any letter united... | |
| James Wood - Algebra - 1845 - 442 pages
...beginning from 0, is increased by unity, in every succeeding term. Also the coefficient of each term is found by multiplying the coefficient of the preceding term by the index of o> in that term, and dividing by the index of a increased by unity. 6.5 6.5.4 6.5.4.3 Thus (x + aY... | |
| Charles William Hackley - Algebra - 1846 - 544 pages
...(x-^-a)s is 2, of (j+a)6 is 6, of (x+a)' is 7. IV. The coefficient of any term after the second may bo found by multiplying the coefficient of the preceding...term by the index of x in that term, and dividing by the number of terms preceding the required term. Thus, in the expansion of (x+a)'t the coefficient... | |
| John Bonnycastle - 1848 - 334 pages
...Note. 2. The coefficient of any term in the formula (1) may be found from that of the preceding term, by multiplying the coefficient of the preceding term by the index of a in that term, and dividing the product by the number of the s/ime term, reckoning from the first... | |
| Stephen Chase - Algebra - 1849 - 348 pages
...and (4.) that of the second term (ie of both x and a) is n. (5.) The coefficient of any term whatever after the first is found by multiplying the coefficient of the preceding term by the exponent of the leading quantity in that term, and dividing by the number of terms preceding the required... | |
| Royal Military Academy, Woolwich - Mathematics - 1853 - 474 pages
...the last but one are each the same as the index of the given power, and the coefficient of any term is found by multiplying the coefficient of the preceding term by the index of the power of the leading quantity in it, and dividing the product either by the number of terms to... | |
| Samuel Alsop - 1857 - 150 pages
...second term is the index of the power of the binomial. 3. The succeeding coefficients are determined by multiplying the coefficient of the preceding term by the index of the leading quantity in that term, and dividing the product by that of the other quantity increased... | |
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