| Charles Vyse - Arithmetic - 1785 - 325 pages
...its Diameter is 8000 Miles ? PROBLEM VII. To find the Area of a Circle. RULES. 1 . Multiply Half the **the Circumference by Half the Diameter, and the Product will be the Area.** Or, 2. Multiply the Square of the Diameter by ,78,54, and' the Product will be the Area. Or, • 3.... | |
| Peter Nicholson - 1809 - 426 pages
...the greater segment. PROBLEM XVI. To find the area of a circle, the diameter being given. METHOD I. **Multiply half the circumference by half the diameter, and the product will be the area.** i EXAMPLE I. What u the area nf a circle lahose diameter is 28 feet, and its circumference 88 feet?... | |
| Charles Vyse - Arithmetic - 1815 - 320 pages
...perfectly round, and its diameter be 8000 miles? PROBLEM' VIL To find the area of a circle. RULES. ' 1. **Multiply half the circumference by half the diameter, and the product will** he the area. Or, 2. Multiply the square of the diameter by ,7854, and the product will be the area.... | |
| Jacob Willetts - Arithmetic - 1822 - 191 pages
...circumference to the diameter ; Or; as 3. 1416 is to 1, so is the circumference to the diameter. III. **.Multiply half the circumference by half the diameter and the product will be the area.** Or multiply the square of the diameter by. 7854, and the pro* duct will be the area. Or multiply the... | |
| William Jillard Hort - 1822 - 308 pages
...opposite angle, and half the product will be the area. Problem. To find the area of a circle. Rule 1. **Multiply half the circumference by half the diameter, and the product will be the area.** Rule 2. Multiply the square of the diameter by 7854', and the product will be the area. ProUem. To... | |
| Nicolas Pike - Arithmetic - 1822 - 560 pages
...of the arch line ABC, and by Art. 24, the diameter FB ; then multiply half the chord of the arch ABC **by half the diameter, and the product will be the area of the** sector ABCE : then find the area of the triangle AEC, wboae base AC is 172, and perpendicular height... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...may consult Marrat's Mechanics. Article 768. PROBLEM XV. To find the area of a circle. RULES. _ , 1. **Multiply half the circumference by half the diameter, and the product will be the area.** Or, divide the product of the whole circumference and diameter by 4t9 and the quotient will be the... | |
| Peter Nicholson - Mathematics - 1825 - 372 pages
...of the greater segment. Prob. 1 6. To find the area of a circle, the diameter being given. Method 1. **Multiply half the circumference by half the diameter, and the product will be the area.** Ex. l. What is the area of a circle whose diameter is 28 feet, and iU circumference 88 feet ? Method... | |
| Zadock Thompson - Arithmetic - 1826 - 164 pages
...miles, what is its diameter ? Ans. 79571 nearly. Problem VI. To find the area of a circkj RULE. — **Multiply half the circumference by half the diameter, and . the product will be the area.** * These three methods do not exactly agree, but the last is the most correct. The exact proportion... | |
| Martin Ruter - Arithmetic - 1828 - 180 pages
...diameter to the circumference. ARTICLE V. To find the superficial contents, or area, of a circle. RULE. **Multiply half the circumference by half the diameter, and the product will be the** answer. Or, multiply the square of the diameter by .7854; or multiply the square of the circumference... | |
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