The Computist's Manual of Facts: And Merchant's and Mechanic's Calculator and Guide; Or, A Complete Library of Numerical, Arithmetical and Mathematical Facts, Tables, Data, Formulas and Practical Rules, for the General Business Man, Merchant, Mechanic and Accountant |
From inside the book
Results 1-5 of 32
Page iv
... obtained , relating mainly to machinery and the arts ; and to these sources the author and compiler feels himself much indebted . The conciseness with which the work is generally written would , perhaps , be found an objection , were it ...
... obtained , relating mainly to machinery and the arts ; and to these sources the author and compiler feels himself much indebted . The conciseness with which the work is generally written would , perhaps , be found an objection , were it ...
Page 57
... obtained by multiplying its cubic contents ( feet or inches ) by the weight ( pounds , ounces , or grains ) of a cubic foot or inch of the article sought to be weighed ; that is Length breadth × thickness × weight per unity of measure ...
... obtained by multiplying its cubic contents ( feet or inches ) by the weight ( pounds , ounces , or grains ) of a cubic foot or inch of the article sought to be weighed ; that is Length breadth × thickness × weight per unity of measure ...
Page 62
... obtain the weight of pipes by means of the above TABLE — RULE . - Multiply the diameter of the pipe , taken from the interior surface of the metal on the one side to the exterior surface on the opposite , ( interior diameter + thickness ...
... obtain the weight of pipes by means of the above TABLE — RULE . - Multiply the diameter of the pipe , taken from the interior surface of the metal on the one side to the exterior surface on the opposite , ( interior diameter + thickness ...
Page 63
... obtain the same result . EXAMPLE.Required the weight of a cast iron shell whose ex- terior diameter is 10 inches and interior diameter 8 inches . 10383.1365 66.612 lbs . Ans . MENSURATION OF LUMBER . To find the contents of a WEIGHT OF ...
... obtain the same result . EXAMPLE.Required the weight of a cast iron shell whose ex- terior diameter is 10 inches and interior diameter 8 inches . 10383.1365 66.612 lbs . Ans . MENSURATION OF LUMBER . To find the contents of a WEIGHT OF ...
Page 66
... obtained by the method referred to . Thus , suppose the stick a cylinder , 28 inches in diameter , and 40 feet in length ; and we have , by the falla- cious rule , as above , 134.44 cubic feet ; and— By a correct method , we have ...
... obtained by the method referred to . Thus , suppose the stick a cylinder , 28 inches in diameter , and 40 feet in length ; and we have , by the falla- cious rule , as above , 134.44 cubic feet ; and— By a correct method , we have ...
Common terms and phrases
12 feet 12 inches 30 inches A B C abscissa add the square altitude angle opposite arithmetical progression base bisect breadth bung diameter Camphene cantaro cask cast iron cent centre circumference cone copper cosec cosine cube cubic feet cubic foot cubic inches cylinder decimal denominator describe the arcs diagonal distance divide the product dividend divisor ellipse equal EXAMPLE figure find the area find the numbers find the solidity fraction frustum geometrical progression given circle given number greater extreme half the arc head diameter hypotenuse interior diameter less extreme measure Multiply the square multiply the sum number of terms number of things ordinate parabola perpendicular pipe plane pound quantity quotient radius rhombus right-angled triangle rods RULE RULE.-Multiply segment side slant height specific gravity square root subtract surface tangent thickness ullage velocity VULGAR FRACTIONS weight wheel whole numbers
Popular passages
Page 132 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 123 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 175 - So IS THE AREA OF THE CIRCLE, TO THE AREA OF THE SECTOR.
Page 224 - G, the distance of the centre of gyration from the axis of motion, t, the time the force acts, v the velocity acquired by the revolving body in that time.
Page 104 - To reduce a whole number to an equivalent fraction, having a given denominator. RULE. Multiply the whole number by the given denominator, and place the product over the said denominator, and it will form the fraction required.
Page 133 - Subtract the cube of this number from the first period, and to the remainder bring down the first figure of the next period for a dividend.
Page 119 - Sir," said I, after puzzling a long time over "more requiring more and less requiring less" — "will you tell me why I sometimes multiply the second and third terms together and divide by the first — and at other times multiply the first and second and divide by the third?" "Why, because more requires more sometimes, and sometimes it requires less — to be sure. Haven't you read the rule, my boy?" " Yes, sir, I can repeat the rule, but I don't understand it.
Page 108 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 142 - Multiply continually together all the terms of the natural series of numbers, from 1 up to the given number, and the last product will be the answer.
Page 123 - Divide the amount of the debt at its maturity by one dollar plus its interest for the given time and rate and the quotient will be the present worth. Subtract the present worth from the amount...