## The Essentials of Geometry (plane) |

### From inside the book

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**Draw**a straight**line**CD in such a position that angle BCD shall be less than angle ACD ; and let**line**CD be turned about point C as a pivot towards the position CA. Then , angle BCD will constantly increase ; and angle ACD will ... Page 9

... line . To prove the sum of angles ACD and BCD equal to two right angles .

... line . To prove the sum of angles ACD and BCD equal to two right angles .

**Draw line**CE perpendicular to AB at C. [ At a given point in a straight line , a perpendicular to the line can be drawn . ] ( § 25 ) Then , it is evident that ... Page 14

Webster Wells. F A D B II . Given line CD 1 to line AB at its middle point D , Fany point without CD , and lines AF and BF . To Prove AF > BF . Proof . Let AF intersect CD at E , and

Webster Wells. F A D B II . Given line CD 1 to line AB at its middle point D , Fany point without CD , and lines AF and BF . To Prove AF > BF . Proof . Let AF intersect CD at E , and

**draw line**BE . Now BE + EF > BF . [ A str . line is ... Page 15

... line can be drawn . ] ( § 25 ) Apply line FG to line AB , and move it along until HK passes through C ; let point H fall at D , and

... line can be drawn . ] ( § 25 ) Apply line FG to line AB , and move it along until HK passes through C ; let point H fall at D , and

**draw line**CD . Then , CD is 1 AB . If possible , let CE be another from C to AB . Produce CD to C ... Page 16

... line that can be drawn from a point to a straight line . A -B D Given CD the L from point C to line AB , and CE any other str . line from C to AB . To Prove CD < CE . = Proof . Produce CD to C ' , making C'D CD , and

... line that can be drawn from a point to a straight line . A -B D Given CD the L from point C to line AB , and CE any other str . line from C to AB . To Prove CD < CE . = Proof . Produce CD to C ' , making C'D CD , and

**draw line**EC ' . By ...### Other editions - View all

### Common terms and phrases

ABē AC and BC ACē ADē adjacent angles altitude angles are equal apothem approach the limit arc BC BCē bisector bisects centre cents chord circumference circumscribed common point construct the triangle Converse of Prop decagon diameter Draw line EFGH equal angles equal respectively equally distant equiangular equiangular polygon equivalent exterior angle Given line given point given straight line homologous sides hypotenuse intersecting isosceles triangle line CD line joining measured by arc meeting middle point non-parallel sides number of sides opposite sides parallel parallelogram perimeter perpendicular points of sides polygons AC produced Prove Proof quadrilateral radii radius ratio rectangle regular inscribed regular polygon rhombus right angles right triangle segments side BC sides are equal similar triangles subtended tangent THEOREM transversal trapezoid triangles are equal vertex

### Popular passages

Page 220 - The perpendiculars from the vertices of a triangle to the opposite sides are the bisectors of the angles of the triangle formed by joining the feet of the perpendiculars.

Page 39 - If two triangles have two sides of one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second.

Page 47 - ... the three sides of one are equal, respectively, to the three sides of the other. 2. Two right triangles are congruent if...

Page 69 - A chord is a straight line joining the extremities of an arc ; as AB.

Page 147 - If one leg of a right triangle is double the other, the perpendicular from the vertex of the right angle to the hypotenuse divides it into segments which are to each other as 1 to 4.

Page 188 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.

Page 138 - In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Page 159 - DB as often as possible. As the lines AD and DB are incommensurable, there must be a remainder, B'B, less than one of the equal parts. Draw B'C

Page 47 - Two triangles are congruent if two sides and the included angle of one are equal respectively to two sides and the included angle of the other.