 | Mathematics - 1801 - 658 pages
...breadth of the street. • t Ans. 76- 1 2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A ABD+... | |
 | Abel Flint - Surveying - 1804 - 226 pages
...8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the Sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area.... | |
 | Abel Flint - Surveying - 1808 - 190 pages
...the double Area of the Triangle. • PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area.... | |
 | Thomas Keith - 1817 - 306 pages
...acres. <• 2 roods 21 perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Example 1. Let AB c D JE. be a trapezoid, the side '-. A )•. — 23,... | |
 | Matthew Iley - 1820 - 512 pages
...of a Quadrilateral having two Parallel unequal Sides. RULE. By the Pen. Multiply half the sum of the parallel sides by the perpendicular distance between them, and divide the product by the number of cubic inches in the proposed integer. By the Sliding Rule. Set the gage-point, for tlie... | |
 | Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...the grain? Ant. 97.3383 bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area in square inches. Divide this area by 2 82, 231, and 2150.42, and... | |
 | John Nicholson - Machinery - 1825 - 838 pages
...when the squre of AB has been subtracted. 63 I 189 3 1 189 Prot. 4. To find the Area ofaTrapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and... | |
 | Abel Flint - Surveying - 1825 - 252 pages
...0.47076=4201 tbe double Area of the Triangle. PROBLEM X. To find the Jbeaof a TrapezoiA. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance, the product will be the Area.... | |
 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...the area ? Ans. 54.299 rods. I Problem III. Tojind the area of a trapezoid. :BuLE.— Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Examples. 1. One of the two parallel sides of a trapezoid is 7.5 chains... | |
 | John Nicholson (Civil engineer) - Building - 1830 - 240 pages
...when the square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and... | |
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To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides "by the perpendicular distance between them : the product will be the area. 
