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" The area of a rectangle is found by multiplying its length by its breadth. "
Modern Intermediate Arithmetic, by Bruce M. Watson and Charles E. White ... - Page 105
by Bruce Mervellon Watson - 1922 - 278 pages
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A Written Arithmetic, for Common and High Schools: To which is Adapted a ...

George Augustus Walton - Arithmetic - 1864 - 364 pages
...whose angles are right angles. (Art. 191.) 172. A square is a rectangle whose sides are all equal. 173. The area of a rectangle is found by multiplying its length by its breadth. ILLUSTRATION I. Suppose the length of the figure A, B, C, D, to be 4 inches, and its breadth 3 inches....
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A Written Arithmetic, for Common and High Schools: To which is Adapted a ...

George Augustus Walton - Arithmetic - 1864 - 376 pages
...whose angles are right angles. (Art. 191.) 172. A square is a rectangle whose sides are all equal. 173. The area of a rectangle is found by multiplying its length by its breadth. ILLUSTRATION I. Suppose the length of the figure A, B, C, D, to be 4 inches, and its breadth 3 inches....
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Written Arithmetic

George Augustus Walton - 1876 - 358 pages
...whose angles are right angles. (Art. 191.) 172. A square is a rectangle whose sides are all equal. 173. The area of a rectangle is found by multiplying its length by its breadth. ILLUSTRATION I. Suppose the length of the figure A, B, C, D, to be 4 inches, and its breadth 3 inches....
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An Elementary Course of Instruction for Mine Foremen and Pit Bosses

Floyd Davis - Mining engineering - 1900 - 148 pages
...2 4 25 Hence a side of the square is 45 feet Q. 77. How is the area of a rectangle determined'/ A. The area of a rectangle is found by multiplying its length by its breadth. Q. 78. How many square feet are contained in 20 boards, each 18 feet long by 18 inches wide? A. 18...
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A Grammar School Arithmetic

L. V. Arnold - Arithmetic - 1911 - 186 pages
...ft. wide and 11 ft. high, side walls and ceiling : one bundle is estimated to cover 6 sq. yd. AREAS The area of a rectangle is found by multiplying its length by its breadth times the unit. Find the area of rectangles. 1. 17ft. X 45 ft. area in sq. yd. 2. 35 rd. X 10 rd. area...
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General Physics for Students: A Text-book on the Fundamental Properties of ...

Edwin Edser - Physics - 1913 - 656 pages
...in question is related to the three fundamental units of length L, mass M, and time T. For instance, the area of a rectangle is found by multiplying its length by its breadth, ie , by multiplying together two magnitudes each of which represents a certain number of units of length...
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Modern Intermediate Arithmetic

Bruce Mervellon Watson, Charles Edward White - Arithmetic - 1918 - 276 pages
...AN OBLONG 1. How many right angles has the square ? How many sides? 2. How many right angles has-the oblong ? How many sides? A figure that is bounded...Such problems may be shortened by cancellation, thus: 23 X 44 - 7 acres Ar?s 28 x 40 " 7 The number of square rods is ff " The number of acres is 28 X i...
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Beginners' Algebra

Clarence Elmer Comstock, Mabel Sykes - Algebra - 1922 - 332 pages
...150 feet deep? How would you find the area of a card having square corners ? In words the answer is : The area of a rectangle is found by multiplying its length by its width. This rule may be stated more briefly by the omission of unnecessary words and by the use of...
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GCSE Intermediate Mathematics: A Full Course

L. Bostock - Juvenile Nonfiction - 1996 - 484 pages
...problem. For example, the formula for finding the area of a rectangle can be written in words as follows. The area of a rectangle is found by multiplying its length by its width. This formula works for any rectangle, ie the length and the width of the rectangle can each...
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California Real Estate Principles

Charles O. Stapleton, Martha R. Williams - Business & Economics - 2007 - 508 pages
...9.37 9.77 10.16 40 4.83 5.16 5.51 5.86 6.22 6.59 6.96 7.34 7.72 8.11 8.49 8.89 9.28 9.68 10.08 90 _ 90 The area of a rectangle is found by multiplying its length by its width. Only units of like measure can be multiplied by each other in deriving area, and the answer...
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