 | Charles Davies, William Guy Peck - Electronic book - 1855 - 592 pages
...angle equal in each, arc to each other as the products of the including sides. The area of a plane triangle is equal to one half the product of its base and altitude. If we denote the base by b, the altitude by A. and the area bv Л', the sides and angles being denoted... | |
 | Aeronautical Society of Great Britain - Aeronautics - 1883 - 488 pages
...base b and altitude a be rotated about its base, the resistance which it experiences is JB. But the area of a triangle is equal to one half the product of its base on altitude, and coasequently that spoken of has only •£ the area of the rectangle, therefore, suppose... | |
 | Isaac Sharpless - Geometry - 1879 - 282 pages
...altitude. For it is equal to a rectangle of the same base and altitude (I. 33). Corollary 2.—The area of a triangle is equal to one half the product of its base and altitude. For a triangle is one half a rectangle of the same base and altitude (I. 35, Cor.). Proposition 17.... | |
 | George Albert Wentworth - Geometry, Analytic - 1886 - 334 pages
...^iy2 — 2-sy2 .-. area =| [a?i (y2 - ys) + x^ (ys -yi)+ xs (j/ij/2)]. [13] SOLUTION II. Since the area of a triangle is equal to one half the product of its base and its altitude, this problem may be solved as follows : (i) Find the length of any side as base, (ii)... | |
 | William Shaffer Hall - Measurement - 1893 - 88 pages
...20. To find the area of a triangle, when two sides and their included angle are given. [12] RULE: The area of a triangle is equal to one- half the product of two sides into the sine of their included angle. PIG. 4. Proof Let ABC, Fig. 4, represent a plane triangle,... | |
 | Charles Ambrose Van Velzer, George Clinton Shutts - Geometry - 1894 - 522 pages
...the original polygon. Continue the process until the polygon is reduced to a triangle. Ex. 189. The area of a triangle is equal to one half the product of its perimeter by the radius of the inscribed circle. PROPOSITION XX. PROBLEM. 286. To find two straight... | |
 | Wm. M. Peck - 1894 - 310 pages
...perpendicular distance from the base, or the base produced, to the Fi g- 6 vertex. (Fig. 5). | e. The area of a triangle is equal to one \ half the product of the numbers represent- \* ing its base and height. (Fig. 6). In a right triangle the following names... | |
 | Adelia Roberts Hornbrook - Geometry - 1895 - 222 pages
...triangles in the same way, by taking half the product of the base and altitude. PRINCIPLE 22. — The area of a triangle is equal to one half the product of its base and altitude. 96. Draw a triangle and show in what way you find its area. 97. Find the area of a triangle whose base... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 374 pages
...parallelograms having equal altitudes are to each other as their bases. PROPOSITION VI. THEOREM 370. The area of a triangle is equal to one -half the product of its base and altitude. 112 GIVEN the triangle ABC with base b and altitude a. To PROVE area AB C = \ a X b. From C draw CX... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 376 pages
...parallelograms having equal altitudes are to each other as their bases. PROPOSITION VI. THEOREM 370. The area of a triangle is equal to one -half the product of its base and altitude. b B GIVEN the triangle ABC with base b and altitude a. To PROVE area ABC = iax b. From Cdravv CX parallel... | |
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The area of a triangle is equal to one half 'the product of its base and altitude. 
