| Adrien Marie Legendre - Geometry - 1822 - 394 pages
...equal. In the same manner it may be shewn, that B is equal to E, and C to F. PROPOSITION XII. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. LET the side AB be equal to AC, the angle C will be equal to B. Join A the vertex, and D the middle... | |
| Adrien Marie Legendre - Geometry - 1836 - 394 pages
...thus, the equal angles D and A, lie opposite the equal sides EF and BC. . PROPOSITION XI. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. Let the side BA be equal to the side AC ; then will the angle C be equal to the angle B. For, join... | |
| Benjamin Peirce - Geometry - 1837 - 216 pages
...eqnnl to those of another, the other sides and angle are also equal in the two triangles. 55. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Equal Angles of the Isosceles Triangle. Demonstration. In the isosceles triangle ABC (fig. 32), let... | |
| Nicholas Tillinghast - Geometry, Plane - 1844 - 110 pages
...and DF be equal to AC, EF equal to BC, and the angle at F equal to the angle atC. PROP. VI. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. Fig. 6. 11 Let AB, BC, be the equal sides ; then we have to prove that the angle A is equal to £_... | |
| Benjamin Peirce - Geometry - 1847 - 204 pages
...equal to those of another, the other sides and angle are also equal in the two triangles. 55. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Proof. In the isosceles triangle ABC (fig. 32), let the equal sides be AB and BC. Equal Angles of the... | |
| Charles Davies - Trigonometry - 1849 - 372 pages
...thus, the equal angles D and A, lie op posite the equal sides EF and BC. • PROPOSITION XI. THEOREM. In an isosceles triangle, the angles opposite the equal sides are equal. For, join the vertex A, and D the middle point of the base BC. Then, the triangles BAD, DAC, will have... | |
| American Association for the Advancement of Science - 1855 - 396 pages
...the observer at 0', then O' M = his latitude, and PM = 90° ; therefore P D' = • J (90° + lat.). In an isosceles triangle the angles opposite the equal sides are equal ; therefore the angle DPC = DOC, but DOC is the azimuth of the object ; therefore the hour-angle of... | |
| Charles Davies - Geometry - 1850 - 218 pages
...coincide with the parts of the triangle DEF, and therefore, the two triangles are equal, THEOREM VI. In an isosceles triangle the angles opposite the equal sides are equal to each other, C Let ABC be an isosceles triangle, having the side AC equal to the side CB : then will... | |
| Charles Davies - Geometry - 1850 - 238 pages
...coincide with the parts of the triangle DEF, and therefore, the two triangles are equal. THEOREM VI. •In an isosceles triangle the angles opposite the equal sides are equal to each other, Let ABC be an isosceles triangle, having the side AC equal to the side CB : then will... | |
| Charles Davies - Geometry - 1886 - 340 pages
...coincide with the parts of the triangle DEF, and therefore, the two triangles arc equal THEOREM V1. In an isosceles triangle the angles opposite the equal sides are equal to each other. r* Let ABC be an isosceles triangle, having the side AC equal to the side CB: . then... | |
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