 | Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 446 pages
...(a+b+c) (d+f)=ad + bd+cd + af+bf+cf. Therefore, in order to multiply together two polynomials composed entirely of additive terms, multiply successively...the rule given for the multiplication of monomials. (No. 16.) For example : (3a3+4a b + b3) (2a + 5b) gives for a product 6a3 + 8a3 b + 2ab3 + 15 a3 b... | |
 | Charles Davies - Algebra - 1835 - 378 pages
...(a+b+c) (d+f)=ad+bd+cd+af+bf+cf. Therefore, in order to multiply together two polynomials composed entirely of additive terms, multiply successively...products. If the terms are affected with co-efficients and exponents,observo the rule given for the multiplication of monomials (Art. 41). For example, multiply... | |
 | James Bryce - Algebra - 1837 - 322 pages
...7. CASE III. When both multiplier and multiplicand are compound quantities. RULE. 38. Multiply every term of the multiplicand by each term of the multiplier, and add the several products thus obtained. It is obvious from the note to page 22, and from Art. 11, that... | |
 | Algebra - 1838 - 372 pages
...entire product . . ad+bd+cd+af+bf+cf. Therefore, in order to multiply together two polynomials composed entirely of additive terms, multiply successively...multiplication of monomials (Art. 41). For example, multiply . . 3a?+4ab-\-b2 by .... 2a + 5b The product, after reducing, +15a26+20o62+563 becomes . . . 6a3+23a2b+22ab'*+5b3.... | |
 | Algebra - 1839 - 368 pages
...entire product . . ad+bd+cd+af+bf+cf. Therefore, in order to multiply together two polynomials composed entirely of additive terms, multiply successively...the multiplier, and add together all the products. Multiply by . . 3a3i . 2ia3 . (4) , . 12a3* . , . 12a;3y . (5) , . &xyz . ay*z (6) If the terms are... | |
 | Charles Davies - Algebra - 1839 - 272 pages
....... ad-}-lid-\-cd-\-af-\-bf-\-cf. Therefore, in order to multiply together two polynomials composed entirely of additive terms : Multiply successively...the multiplier, and add together all the products. EXAMPLES. 1. Multiply ..... 3(P by ..... , 2i2 + 5b 6a2+ The product, after reducing, +15a~b+20ab*+5b^... | |
 | Charles Davies - Algebra - 1839 - 264 pages
...together two polynomials composed entirely of additive terms : Multiply successively each term of tlic multiplicand by each term of the multiplier, and add together all the products. EXAMPLrls. 1. Multiply ..... 5a-+ 4sJ-f-62 by ...... 2a + 5b The product, after reducing, +15a26+20a62+563... | |
 | Charles Davies - Algebra - 1842 - 284 pages
...entire product .... ad+bd+cd+af+bf+cf. Therefore, in order to multiply together two polynomials composed entirely of additive terms : Multiply successively...the multiplier, and add together all the products. EXAMPLES. 1. Multiply ..... 3a2+ 4a6+62 by ...... 2a + 5b _ 6a3+ 8cPb+2abz The product, after reducing,... | |
 | Elias Loomis - Algebra - 1846 - 376 pages
...sign minus: (55.) The following rule then comprehends the whole doctrine of multiplication. Multiply each term of the multiplicand, by each term of the multiplier, and add together all the partial products, observing that like signs require + in the product, and unlike signs — . EXAMPLE... | |
 | Elias Loomis - Algebra - 1846 - 380 pages
...sign minus: (55.) The following rule then comprehends the whole doctrine of multiplication. Multiply each term of the multiplicand, by each term of the multiplier, and add together all tht partial products, observing that like signs require + in the product, and unlike signs — . EXAMPLE... | |
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Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 
