Elements of Geometry |
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Page x
... square , of this number ; 5 × 5 , or 25 , is the second power , or square , of 5 . The second power therefore is the product of two equal fac- tors ; each of these factors is the square root of the product ; 5 is the square root of 25 ...
... square , of this number ; 5 × 5 , or 25 , is the second power , or square , of 5 . The second power therefore is the product of two equal fac- tors ; each of these factors is the square root of the product ; 5 is the square root of 25 ...
Page 2
... square ( fig . 11 ) , which has its sides equal and its angles right angles , ( See art . 80 ) ; The rectangle ( fig . 12 ) , which has its angles right angles with- out having its sides equal ( See art . above referred to ) ; The ...
... square ( fig . 11 ) , which has its sides equal and its angles right angles , ( See art . 80 ) ; The rectangle ( fig . 12 ) , which has its angles right angles with- out having its sides equal ( See art . above referred to ) ; The ...
Page 19
... square and rectangle ( 17 ) . 11 . 81. Corollary . The sum of the angles of a pentagon is equal to two right angles multiplied by 5-2 , which makes 6 right angles ; therefore , when a pentagon is equiangular , each angle is equal to a ...
... square and rectangle ( 17 ) . 11 . 81. Corollary . The sum of the angles of a pentagon is equal to two right angles multiplied by 5-2 , which makes 6 right angles ; therefore , when a pentagon is equiangular , each angle is equal to a ...
Page 38
... 148. Corollary . If the given angle be a right angle , the figure will be a rectangle ; and , if the adjacent sides are also equal , the figure will be a square . PROBLEM . 149. To find the centre of a given 38 Elements of Geometry .
... 148. Corollary . If the given angle be a right angle , the figure will be a rectangle ; and , if the adjacent sides are also equal , the figure will be a square . PROBLEM . 149. To find the centre of a given 38 Elements of Geometry .
Page 41
... square . But , although the exact ratio cannot be found in numbers , by neglecting the last remainder we may find an approximate ratio to a greater Geom . 6 or less degree of exactness , according as the operation Problems . 41.
... square . But , although the exact ratio cannot be found in numbers , by neglecting the last remainder we may find an approximate ratio to a greater Geom . 6 or less degree of exactness , according as the operation Problems . 41.
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Common terms and phrases
ABC fig adjacent angles altitude angle ACB angle BAD base ABCD bisect centre chord circ circular sector circumference circumscribed common cone consequently construction convex surface Corollary cube cylinder Demonstration diagonals diameter draw drawn equal and parallel equiangular equilateral equivalent faces figure four right angles frustum Geom gles greater hence homologous sides hypothenuse inclination inscribed circle isosceles join less let fall line AC manner mean proportional measure the half meet multiplied number of sides oblique lines opposite parallelogram parallelopiped perimeter perpendicular plane MN polyedron prism proposition pyramid S-ABC quadrilateral radii radius ratio rectangle regular polygon right angles right-angled triangle Scholium segment semicircumference side BC similar solid angle sphere spherical polygons spherical triangle square described straight line tangent THEOREM three plane angles triangle ABC triangular prism triangular pyramids vertex vertices whence