| Robert Simson - Trigonometry - 1775 - 534 pages
...for a diftance, let a circle be defcribed, meeting AC produced in E, F, and BCinD; join DA, EB, FB; and draw FG parallel to BC, meeting EB in G. The angle EAB (32. i.) is equal to the fum of the angles at the bafe, and the angle EFB at the circumference is equal... | |
| Robert Simson - Trigonometry - 1781 - 534 pages
...a diflance, let a circle be defcribed, meeting AC produced in E, F, and BC in D ; join DA, EB, FB ; and draw FG parallel to BC, meeting EB in G. The angle EAB (32. i.) is equal to the fum of the tmgles at the bafe, and the angle EFB at the circumference is equal... | |
| Euclid - 1781 - 552 pages
...a diftancc, let a circle be delcribed, meeting AC produced in E, F, and BCin D ; join DA, EB, FB ; and draw FG parallel to BC, meeting EB in G. The angle EAB (32. j.) is equal to the fum of the angles at the bafe, and the angle EFB at the circumference is equal... | |
| Robert Simson - Trigonometry - 1804 - 530 pages
...a diftance, let a circle be defcribed, meeting AC produced in E, F, and BC in D ; join DA, EB, FB ; and draw FG parallel to BC, meeting EB in G. The angle EAB (32. i.) is equal to the fum of the angles at the bafe, and the angle EFB at the circumference is equal... | |
| Euclides - 1816 - 588 pages
...a distance, let a circle be described, meeting AC, produced in E, F, and BC in D; join DA, EB, FB; and draw FG parallel to BC, meeting EB in G. The angle EAB (32. 1.) is equal to the sum of the angles at the base, and the angle EFB at the circumference is equal... | |
| Robert Simson - Trigonometry - 1827 - 546 pages
...distance, let a circle be described, meeting AC, produced in E, F, and BC in D ; join DA, EB, FB ; and draw FG parallel to BC, meeting EB in G. The angle EAB (32. 1.) is equal to the sum of the angles at the base, and the angle EFB at the circumference is equal... | |
| Euclides - 1834 - 518 pages
...distance, let a circle be described, meeting AC, produced in E, F, and BC in D ; join DA, EB, FB ; and draw FG parallel to BC, meeting EB in G. The angle EAB * is equal to the sum of the angles at the base, and the angle EFB at the circumference is equal to the half of EAB at... | |
| Euclid - 1835 - 540 pages
...a distance, let a circle be described, meeting AC produced in E, F, and BC in D ; join DA, EB, FB : and draw FG parallel to BC, meeting EB in G. The angle EAB (32. 1.) is equal to the sum of the angles at the base, and the angle EFB at the circumference is equal... | |
| John Playfair - Geometry - 1836 - 148 pages
...a distance, let a circle be described, meeting AC produced in E, F, and BC in D ; join DA, EB, FB : and draw FG parallel to BC, meeting EB in G. The angle EAB (5. 2.) is equal to the sum of the angles at the %>ase, and the angle EFB at the circumference is equal... | |
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