| Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 446 pages
...the multiplicand, and add together the partial products. Hence, (a+b+c) (d+f)=ad + bd+cd + af+bf+cf. **Therefore, in order to multiply together two polynomials...the rule given for the multiplication of monomials.** (No. 16.) For example : (3a3+4a b + b3) (2a + 5b) gives for a product 6a3 + 8a3 b + 2ab3 + 15 a3 b... | |
| Charles Davies - Algebra - 1835 - 378 pages
...multiplican<l,/times, and add together the partial products. Hence, (a+b+c) (d+f)=ad+bd+cd+af+bf+cf. **Therefore, in order to multiply together two polynomials...products. If the terms are affected with co-efficients and** exponents,observo the rule given for the multiplication of monomials (Art. 41). For example, multiply... | |
| James Bryce - Algebra - 1837 - 322 pages
...7. CASE III. When both multiplier and multiplicand are compound quantities. RULE. 38. Multiply every **term of the multiplicand by each term of the multiplier, and add** the several products thus obtained. It is obvious from the note to page 22, and from Art. 11, that... | |
| Charles Davies - Algebra - 1839 - 272 pages
...Multiplicand ....... a+6+c Multiplier ........ d+f taken d times ....... ad-\-brl-\-cd taken/times ........ **-\-af-\-bf-\-cf entire product .... ad+bd+cd+af+bf+cf....the multiplier, and add together all the products.** EXAMPLES. 1. Multiply ..... 3a2+ by ..... , 2o +56 The product, after reducing, +15a26+20a becomes... | |
| Charles Davies - Algebra - 1839 - 264 pages
...together two polynomials composed entirely of additive terms : Multiply successively each term of tlic **multiplicand by each term of the multiplier, and add together all the products.** EXAMPLrls. 1. Multiply ..... 5a-+ 4sJ-f-62 by ...... 2a + 5b The product, after reducing, +15a26+20a62+563... | |
| Charles Davies - Algebra - 1841 - 264 pages
...a+J+c Multiplier ........ d+f taken d times ....... ad-\-bd-\-cd taken/times ........ -\- of -\-bf-\-cf **entire product .... ad+bd+cd+af+bf+cf. Therefore,...the multiplier, and add together all the products.** EXAMPLES. 1. Multiply ..... 3a2+ 4aJ+42 by ...... 2a + 5J 6a3+ 8a2J+2aJ2 The product, after reducing,... | |
| Charles Davies - Algebra - 1842 - 368 pages
...entire product . . ad+bd+cd+af+bf+cf. Therefore, in order to multiply together two polynomials com posed **entirely of additive terms, multiply successively...multiplication of monomials (Art. 41). For example, multiply** . . 3a 2 +4ai+i 2 by .... 2a +5b 6o 3 + The product, after reducing, + I5a2b+20ab 2 +5b 3 becomes .... | |
| Charles Davies - Algebra - 1842 - 284 pages
...required to take the multiplicand as many times as there are units in d and/. Multiplicand ....... a+6+c **Multiplier ........ d-\-f taken d times ....... ad+bd+cd...the multiplier, and add together all the products.** EXAMPLES. 1. Multiply ..... 3a2+ 4a6+62 by ...... 2a + 5b _ 6a3+ 8cPb+2abz The product, after reducing,... | |
| Elias Loomis - Algebra - 1846 - 376 pages
...sign minus: (55.) The following rule then comprehends the whole doctrine of multiplication. Multiply **each term of the multiplicand, by each term of the multiplier, and add together all the** partial products, observing that like signs require + in the product, and unlike signs — . EXAMPLE... | |
| Elias Loomis - Algebra - 1846 - 380 pages
...sign minus: (55.) The following rule then comprehends the whole doctrine of multiplication. Multiply **each term of the multiplicand, by each term of the multiplier, and add together all** tht partial products, observing that like signs require + in the product, and unlike signs — . EXAMPLE... | |
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