| Abel Flint - Surveying - 1804 - 226 pages
...Angle 28° 5'. 0.47076 105X85=8925, and 8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the Sum of the two parallel Sides... | |
| Abel Flint - Surveying - 1808 - 190 pages
...28* 5'. 0.47076 105x85=8925, and 8925x0.47076=4201 the double Area of the Triangle. • PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides... | |
| Thomas Keith - 1817 - 306 pages
...trapezium 85342'2885 yards, or 17•6327 acres; or 17 acres. <• 2 roods 21 perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Example... | |
| Ira Wanzer - Arithmetic - 1831 - 408 pages
...many acres are contained in a triangle whose sides are 30, 40, and 50 rods? Ans. 3f A. PROBLEM V, — To find the area of a Trapezoid. RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the pr«' duct will be the area.... | |
| Ireland commissioners of nat. educ - 1834 - 370 pages
...as follows, viz. AB 25, AD 34, D С 35, and B С 16 ; required its area ? Ans. 700-99. PROBLEM XIII. To find the area of a Trapezoid RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will give the area.*... | |
| Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...are as follows, viz. AB 25, AD 34, DC 35, and BC 16 ; required its area. Am. 700.99. PROBLEM XIII. To find the area of a Trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will give the area.*... | |
| Charles Guilford Burnham - Arithmetic - 1841 - 324 pages
...The three sides of a triangle are 6, 8 and 10 chains. What is the area ? Answer, 24 chains. To fold the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1.... | |
| P. O'Shaughnessy (Civil engineer) - Civil engineering - 1848 - 110 pages
...of a triangle, having the base 82 chains and the altitude 20. 12 chains. Ans. 82a lr 3|P. Prob. 3. To find the area of a trapezoid. Rule — Multiply half the sum of the two perpendiculars by the base, and the product will be area. (The truth of this rule is manifest,... | |
| Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...318. ATRAPEZOID is a quadrilateral, which has only one pair of its opposite sides parallel. ART. 319. To find the area of a trapezoid. RULE. — Multiply...half the sum of the parallel sides by the altitude, and the product is the area. 1. What is the area of a trapezoid, the longer parallel side QUESTIONS.... | |
| Benjamin Greenleaf - Arithmetic - 1850 - 346 pages
...318. ATBAPEZOID is a quadrilateral, which has only one pair of its opposite sides parallel. ART. 319. To find the area of a trapezoid. RULE. — Multiply half the sum of the parcdlel sides by the altitude, and the product is the area. 1. What is the area of a trapezoid, the... | |
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