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" The first term, ratio, and number of terms given, to find the sum of all the terms. RULE. Find the last term as before, then subtract the... "
The practical calculator: a treatise on arithmetic - Page 181
by C W. Thornhill - 1854
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - Arithmetic - 1785 - 350 pages
...What is the Share of the eldeft? PROPOSITION III. When the firft Term, Ratio, and Number of Terms, are given, to find the Sum of all the Terms. RULE. Find the laft Term as before, from which take the firft, divide the Remainder by the Ratio, lefs one, and to...
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - Arithmetic - 1806 - 342 pages
...is the Share of the eldest ? PROPOSITION III. When the first Term, Ratio, and Numbar of Terms, are given, to find the Sum of all the Terms. RULE. Find the last Term as before, from which take the first : divide the Remainder by the Ratio, less one, and to...
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A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ...

Michael Walsh - Arithmetic - 1807 - 290 pages
...by a« much more ; what was the eldest son's portion ? Ans. .€.25600. The first term, ratio, and number of terms given, to find the sum of all the terms. RULE. Find the last term as before, then subtract the first from it, and divide the remainder by the ratio less one,...
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The Youth's Assistant in Theoretick and Practical Arithmetic

Zadock Thompson - Arithmetic - 1826 - 176 pages
...terms, the common difference, and the sum of all the terms. Problem I. The first term, the last term, and the number of terms given, to find the sum of all the terms. RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer....
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Practical and Mental Arithmetic on a New Plan: In which Mental Arithmetic is ...

Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
...series increases or diminishes. PROBLEM I. — The first term, the last term, (ie the two extremes) and the number of terms given to find the sum of all the terms. RULE. — Multiply the sum of the extremes by half the num. Чег of terms, the product will be the answer....
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The Mercantile Arithmetic, Adapted to the Commerce of the United States, in ...

Michael Walsh - Arithmetic - 1828 - 318 pages
...younger by as much more ; what was the eldest son's portion ? Ans. ¿€25600. The firft term, ratio, and number of terms given, to find the sum of all the terms. RULE. Find the last term as before, then subtract the first from it, and divide the remainder by the ratio less one,...
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The Mercantile Arithmetic, Adapted to the Commerce of the United States, in ...

Michael Walsh - Arithmetic - 1828 - 318 pages
...as much more ; what was the eldest son'* portion I Ans. £25600. The first term, ratio, and numl.T of terms given, to find the sum of all the terms. RULE. Find the last term as before, then subtract the first from it. and divide the remainder by the ratio less one,...
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Connolly's Arithmetic: Or, The Ohio Accomptant: Being a Plain Practical ...

James L. Connolly (mathematician.) - Arithmetic - 1829 - 266 pages
...3+11 = 14* and 5+9=14. Progressions are best understood by Algebra. The first term, the last term, and the number of terms, given to find the sum of all the terms. RULB. Multiply the sum of the two extremes by the number of terms, and half that product will be the...
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The Tutor's Assistant: Being a Compendium of Arithmetic and a Complete ...

Francis Walkingame - 1832 - 224 pages
...younger by ai much more ; what was the eldest son's portion ? Ant. ££5600. The first term, ratio, and number of terms given, to find the sum of all the terms. RULE. Find the last term as before, then subtract the firxt from it, and divide the remainder by the ratio, less 1...
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The Tutor's Assistant: Being a Compendium of Practical Arithmetic, for the ...

Francis Walkingame - 1833 - 204 pages
...fortune ? Ans. £25000. Case 2. The less extreme, the ratio, and the number of terms being given, toßnd the sum of all the terms. RULE. Find the greater extreme...divide the difference between the extremes by the ra/io less 1 : to the quotient add the greater extreme, 'for the sum required. This is Theorem II....
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