| Anthony Nesbit, W. Little - Measurement - 1822
...met with in Practice ; if, however, they should occur, their contents may be found by the following **Rule : To the square of the radius of the base add the square of the diameter** taken in the middle between the base and the vertex ; then this sum being multiplied by the depth,... | |
| Anthony Nesbit - Measurement - 1824 - 434 pages
...and wine gallons ? Ans. 40.7071 ale, and 4<M>944 wine gallons. PROBLEM XIX. To find the solidity of **a hyperboloid. RULE. To the square of the radius of...of the diameter in the middle between the base and** the vertex ; then this sum being multiplied by the altitude, and the product thus obtained by .5236,... | |
| John Bonnycastle - Geometry - 1829 - 252 pages
...end 48, and the distance of the ends 18 ? Ans. 41733.0144. PROBLEM XXI. To find the solidity of an **hyperboloid. RULE.* To the square of the radius of the base add the square of the** middle diameter between the base and the vertex ; and this sum multiplied by the altitude, and the... | |
| Tobias Ostrander - Measurement - 1834 - 159 pages
...the distance of the ends 10 ? Ans. 23954,7 solidity required. PROBLEM XVII. To find the solidity of **a hyperboloid. Rule — To the square of the radius of the base add the square of the** middle diameter between the base and the vertex, and this sum multiplied by the altitude, and that... | |
| Thomas Holliday - Surveying - 1838 - 80 pages
...inches. Answer, 41733.0144 inches. PROBLEM XIV. TO FIND THE SOLIDITY OF AN HYPERBOLIC CONOID. Rule.—To **the square of the radius of the base, add the square of the** middle diameter between the base and the vertex, and this sum multiplied by the altitude, and the product... | |
| Charles Davies - Geometrical drawing - 1840 - 264 pages
...PROBLEM X. 11. To find the solidity of a spherical segment with one base. RULE. 1st. To three times **the square of the radius of the base add the square of the** height. 2d. Multiply this sum by the height, and the product by the decimal ,5236 : the result will... | |
| Nathan Scholfield - Geometry - 1845 - 506 pages
...Multiply the sum of the areas of the two ends by half their distance. Ex. ]. What is the solid content of **the frustum of a paraboloid, the greater diameter...radius of its base MK=12, and the middle diameter** 230 Here (MK1 + PG1) X KB X .5236 = [12' + (6v/7)"] X 10 X 5.236 = [144 + (6' X 7)] X .5236 = (144... | |
| Nathan Scholfield - Conic sections - 1845
...the greater diameter DC = 30, the least diameter AB=24, and the altitude EF=9 ? . . Ans. 5216.6268. **Ex. 2. What is the content in wine gallons of a cask...MBNM, whose altitude KB=10, the radius of its base** MK.= 12, and the middle diameter PG Here (MK* + PG') X KB X .5236 = [12' + (6-/7)1] X 10 X 5.236 =... | |
| 1845
...for the purpose in the books on mensuration. The practical rule is as follows : — To three times **the square of the radius of the base, add the square of the** versed sine or height; multiply this sum by the height, and the product again by the constant fraction... | |
| Charles Davies - Geometrical drawing - 1846 - 254 pages
...SEGMENTS. 60. How do you find the solidity of a spherical segment with one base ? 1st. To three times **the square of the radius of the base add the square of the** height. 2d. Multiply this sum by the height, and the product by the decimal .5236 ; the result will... | |
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