| Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...met with in Practice ; if, however, they should occur, their contents may be found by the following Rule : To the square of the radius of the base add the square of the diameter taken in the middle between the base and the vertex ; then this sum being multiplied by the depth,... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...and wine gallons ? Ans. 40.7071 ale, and 4<M>944 wine gallons. PROBLEM XIX. To find the solidity of a hyperboloid. RULE. To the square of the radius of...of the diameter in the middle between the base and the vertex ; then this sum being multiplied by the altitude, and the product thus obtained by .5236,... | |
| John Bonnycastle - Geometry - 1829 - 256 pages
...end 48, and the distance of the ends 18 ? Ans. 41733.0144. PROBLEM XXI. To find the solidity of an hyperboloid. RULE.* To the square of the radius of the base add the square of the middle diameter between the base and the vertex ; and this sum multiplied by the altitude, and the... | |
| Tobias Ostrander - Measurement - 1834 - 182 pages
...the distance of the ends 10 ? Ans. 23954,7 solidity required. PROBLEM XVII. To find the solidity of a hyperboloid. Rule — To the square of the radius of the base add the square of the middle diameter between the base and the vertex, and this sum multiplied by the altitude, and that... | |
| Thomas Holliday - Surveying - 1838 - 404 pages
...inches. Answer, 41733.0144 inches. PROBLEM XIV. TO FIND THE SOLIDITY OF AN HYPERBOLIC CONOID. Rule.—To the square of the radius of the base, add the square of the middle diameter between the base and the vertex, and this sum multiplied by the altitude, and the product... | |
| Charles Davies - Geometrical drawing - 1840 - 264 pages
...PROBLEM X. 11. To find the solidity of a spherical segment with one base. RULE. 1st. To three times the square of the radius of the base add the square of the height. 2d. Multiply this sum by the height, and the product by the decimal ,5236 : the result will... | |
| Nathan Scholfield - Geometry - 1845 - 506 pages
...Multiply the sum of the areas of the two ends by half their distance. Ex. ]. What is the solid content of the frustum of a paraboloid, the greater diameter...radius of its base MK=12, and the middle diameter 230 Here (MK1 + PG1) X KB X .5236 = [12' + (6v/7)"] X 10 X 5.236 = [144 + (6' X 7)] X .5236 = (144... | |
| Nathan Scholfield - Conic sections - 1845 - 542 pages
...the greater diameter DC = 30, the least diameter AB=24, and the altitude EF=9 ? . . Ans. 5216.6268. Ex. 2. What is the content in wine gallons of a cask...MBNM, whose altitude KB=10, the radius of its base MK.= 12, and the middle diameter PG Here (MK* + PG') X KB X .5236 = [12' + (6-/7)1] X 10 X 5.236 =... | |
| 1845 - 516 pages
...for the purpose in the books on mensuration. The practical rule is as follows : — To three times the square of the radius of the base, add the square of the versed sine or height; multiply this sum by the height, and the product again by the constant fraction... | |
| Charles Davies - Geometrical drawing - 1846 - 254 pages
...SEGMENTS. 60. How do you find the solidity of a spherical segment with one base ? 1st. To three times the square of the radius of the base add the square of the height. 2d. Multiply this sum by the height, and the product by the decimal .5236 ; the result will... | |
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