 | William Nicholson - Natural history - 1809 - 726 pages
...cylinder is equal to the periphery o< the base multiplied into the length of in side. 3. The solidity of a cylinder is equal to the area of its base, multiplied into its altitude. 4. Cylinders of the same base, ami standing between the same parallels v equal.... | |
 | Edward Augustus Kendall - 1811 - 474 pages
...cylinder is equal to the periphery of the base multiplied into the length of its side. 3. The solidity of a cylinder is equal to the area of its base, multiplied into its altitude. 4. Cylinders of the same base, and standing between the same parallels, are equal.... | |
 | Edward Augustus Kendall - Encyclopedias and dictionaries - 1811 - 482 pages
...cylinder is equal to the periphery of the base multiplied into the length of its side. 3. The solidity of a cylinder is equal to the area of its base, multiplied into its altitude. 4. Cylinders of the same base, and standing between the same parallels, are equal.... | |
 | William Nicholson - Natural history - 1819 - 424 pages
...cylinder is equal to the periphery of the base multiplied into the length of i>s side. 3. The solidity of a cylinder is equal to the area of its base multiplied into its altitude. 4. ' 'ylinders of the same base, and standing between the same parallels, are equal.... | |
 | Timothy Walker - Geometry - 1829 - 138 pages
...are to each other as 4 to 6 or as 2 to 3. Solidity of the Three Round Bodies. 155. — The solidity of a cylinder is equal to the area of its base multiplied by its altitude — . We have already seen (149) that the cylinder may be regarded as a prism of an infinite... | |
 | William Ritchie - Calculus - 1836 - 198 pages
...CK=X, then KD=O - x. By similar triangles, a : b : : x ; FG, hence FG=-? a Again, since the solidity of a cylinder is equal to the area of its base multiplied by its height, the solidity will be expressed by HE2 x .7854 x DK, or using — for .7854, we have — — — (a—... | |
 | James Bates Thomson - Geometry - 1844 - 268 pages
...cire. RCxH. Hence, The convex surface of a cylinder is equal, $e. PROPOSITION II. THEOREM. The solidity of a cylinder is equal to the area of its base, multiplied by its altitude. Let H be the altitude of the given cylinder, RC the radius of its base, and the area of its... | |
 | Dana Pond Colburn - Arithmetic - 1855 - 396 pages
...(p.) The solidity of a prism equals the area of its base multiplied by its altitude. (q.) The solidity of a cylinder is equal to the area of its base multiplied by its altitude. (r.) The convex surface of a cylinder is equal to the circumference of its base multiplied... | |
 | Dana Pond Colburn - Arithmetic - 1856 - 392 pages
...(p.) The solidity of a prism equals the area of its base multiplied by its altitude. (q.) The solidity of a cylinder is equal to the area of its base multiplied by its altitude. (r ) The convex surface of a cylinder is equal to the circumference of its base multiplied... | |
 | Charles Haynes Haswell - Measurement - 1858 - 350 pages
...letting h=b— a(=os), the altitude of tlie cylinder, V = p r2 h ; or, since p r2 = the area of the base, The volume of a cylinder is equal to the area of its base multiplied by its altitude. EXAMPLE 2. To ascertain the Volume of the Frustrum of a Cone with a Circular Base. The generating... | |
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The volume of a cylinder is equal to the area of its base multiplied by the altitude. 
