 | Frederic A. Adams - Arithmetic - 1846 - 230 pages
...first period, and bring down the figures of the next period for a dividend. To the left hand, place double the part of the root already found for a trial divisor. Find by trial, what the next figure of the root must be, and set it down under the first part of the root.... | |
 | Daniel Leach - Arithmetic - 1851 - 280 pages
...period, and to the remainder annex the next period for a partial dividend. Double the figure of the root for a trial divisor. Find how many times this divisor is contained in the partial dividend, omitting the right hand figure, and write the result in the quotient, and also annex... | |
 | Daniel Leach - Arithmetic - 1853 - 622 pages
...period, and to the remainder annex the next period for a partial dividend. Double the figure of the root for a, trial divisor. Find how many times this divisor is contained in the partial dividend, omitting the right hand figure, and icrite the result in the quotient, and also annex... | |
 | Elias Loomis - Algebra - 1855 - 356 pages
...to the remainder bring down the second period for a dividend. 3. Take three hundred times the square of the root already found for a trial divisor; find how many times it is contained in the dividend, and place the quotient for a second figure of the root. 4. Complete... | |
 | Dana Pond Colburn - Arithmetic - 1855 - 396 pages
...hand period, and to the remainder bring down the next period, calling the result a dividend. Fourth. Double the part of the root already found for a trial divisor. Fifth. See how many times this trial divisor is contained in all of the dividend, excepting the right... | |
 | Dana Pond Colburn - Arithmetic - 1856 - 392 pages
...hand period, and to the remainder bring down the next period, calling the result a dividend. Fourth. Double the part of the root already found for a trial divisor. Fifth. See how many times this trial divisor is contained in all of the dividend, excepting the right... | |
 | Joseph Ray - Arithmetic - 1857 - 348 pages
...remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial, divisor. Find how many times this divisor is contained in the dividend, and write the result in the root. Multiply the last figure of the root by the rest. and by 30; square... | |
 | Elias Loomis - Algebra - 1858 - 394 pages
...to the remainder bring down the second period for a dividend. 3. Take three hundred times the square of the root already found for a trial divisor; find how many times it is contained in the dividend, and place the quotient for a second figure of the root. 4. Complete... | |
 | Dana Pond Colburn - 1858 - 288 pages
...left-hand period, and to the remainder bring down the next period, calling the result a dividend. 4th. Double the part of the root already found for a trial divisor. 5th. See how many times this trial divisor is contained in all of the dividend, excepting the right-hand... | |
 | Dana Pond Colburn - Arithmetic - 1860 - 388 pages
...hand period, and to the remainder bring down the next period, calling 'he rtmlt a dividend. Fourth. Double the part of the root already found for a trial divisor. Fifth. Set how many times this trial dirisor is contained in all of the dtcidend, excepting the ri^ht... | |
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Double the part of the root already found for a trial divisor. Find how many times this divisor is contained in the dividend, exclusive of the right-hand figure," and write the quotient as the next figure of the root. 
