| Silas Totten - Algebra - 1836 - 320 pages
...Subtract its cube from the aforementioned period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300, for a divisor. Seek how often the divisor is contained in the dividend, and place the result in the root.... | |
| James Stewart Eaton - Arithmetic - 1857 - 376 pages
...by trial the greatest cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by 3 for a TRIAL... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and place the <fuotient, usually diminished by one o'r two units,... | |
| Benjamin Greenleaf - Arithmetic - 1859 - 334 pages
...Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and place the quotient, usually diminished by one or two units,... | |
| James Stewart Eaton - 1862 - 320 pages
...by trial the greatest cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by § for a TRIAL... | |
| James Stewart Eaton - Arithmetic - 1864 - 322 pages
...by trial the greatest cube in the left-hand period, plac» its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by 3 for a TRIAL... | |
| William Frothingham Bradbury - Algebra - 1868 - 270 pages
...units, thousands, &c. Find the greatest cube in the left-hand period, and place its root at tJie rigM. Subtract this cube from the left-hand period, and to the remainder annex the next period for a dividend. Square the root figure, annex two ciphers, and multiply this result by three for a... | |
| John Groesbeck - Arithmetic - 1868 - 350 pages
...greatest square in the left-hand period, and place its root in the quotient; subtract the square number from the left-hand period, and to the remainder annex the next period of the dividend. III. Double the root already found, for a divisor; find how many times the divisor... | |
| John Groesbeck - Arithmetic - 1868 - 358 pages
...greatest square in the left-hand period, and place its root in the quotient; subtract the square number from the left-hand period, and to the remainder annex the next period of the dividend. III. Double the root already found, for a divisor; find how many times the divisor... | |
| William Frothingham Bradbury - Algebra - 1868 - 264 pages
...square in the left-hand period, and place its root at the right. Subtract the square of this root figure from the left-hand period, and to the remainder annex the next period for a dividend. Double the root already found for a TRIAL DIVISOR, and, omitting the right-hand figure... | |
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