 | Zadock Thompson - Arithmetic - 1832 - 182 pages
...To find the area of a circle. RUXE. — Multiply half the circumference by half the diameter,— or the square of the diameter by .7854, — or the square of the circumference by .07958, — the product will be tho area. 1. What is the area of a circle whose diameter is 7, and circumference... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...To find the area of a circle. ROLE. — Multiply half the circumference by half the diameter,— or the square of the diameter by .7854, — or the square of the circumference by .07938,— the product will be the area. 1. What is the area of a circle whose diameter is 7, and circumference... | |
 | Zadock Thompson - Arithmetic - 1838 - 174 pages
...310. To f.Hrt the area of a cirele. .— Multiply half the cireumference by half the diameter, — or the square of the diameter by .7854, — or the square of the circumference by Xl7D53,-r-the product will be the aren. MENSURATION OF SDPERFICIF.S. 135 1. What M the area of a cirele... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...13 is to 355, so is the diameter to the circumference, &c To find the Area of a Circle. RULE 1. — Multiply the square of the diameter by .7854, or the...square of the circumference by .07958, and the product will be the area. RULE 2.- — Multiply half the circumference by half the diameter. RULE 3. — As... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...is 1923552.2, required the side. Ans. 500. PROBLEM G.—Tofind the area of a circle.* RULE 1 . — Multiply the square of the diameter by .7854, or the square of the radius by 3.1416, or the square of the circumference by .07958 and the product will be the area. EXAMPLES.... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...cylinder 13 feet long, and diameter 4 feet ? PROBLEM XXXI. To find the solidity of a cylinder. RULE. Multiply the square of the diameter by .7854, or the square of the circumference by .07958, and that product by the length will give the solidity. EXAMPLES. 1. How many solid inches are there in... | |
 | Zadock Thompson - Arithmetic - 1848 - 184 pages
...JTo find the area of a circle. RULE. — Multiply half the circumference by half the diameter,— or the square of the diameter by .7854, — or the square of the circumference by .07958, — the product will be the area. 1. What is the area of a circle whose diameter is 7, and circumference... | |
 | Almon Ticknor - Measurement - 1849 - 156 pages
...circumference is 11652-1944 feet? Ans. 3709 feet. PROBLEM 29. To find the area of a circle. RTJLE. — Multiply the square of the diameter by -7854; or,...-07958; and the product in either case will be the area. 1. How many square feet are there in a circle whose diameter is 6-5 feet? Thus, 6-5* = 42-25 x -7854... | |
 | J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...PROBLEM m. To find the Area of a Circle when the Diameter and Circumference are both knospn. Rule. — Multiply the square of the diameter by -7854. Or, the square of the circumference by -07958. -Or, multiply the Circumference by the diameter, and divide the product by 4 ; in either case the product... | |
 | Charles Haynes Haswell - Engineering - 1851 - 346 pages
...is to 355, so is the diameter to the circumference, tc To find the Area of a Circle. i RULE 1. — Multiply the square of the diameter by .7854, or the...square of the circumference by .07958, and the product will be \\.'. area. RULE 2. — Multiply half the circumference by half the diameter. RULE 3. — As... | |
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Multiply the square of the diameter by .7854, or the square of the circumference by .07958. 
