 | Robert Gibson - Surveying - 1806 - 486 pages
...index, will give you the quantity of each respective angle. LEMMA. All, the angles of any polygon, are equal to twice as many right angles as there are sides less by four. Thus aU the angles A, B, C, D, E, F, G, are equal to twice as many right angles as there are... | |
 | Robert Gibson - 1808 - 482 pages
...index, will give you the quantity of each respective angle. LEMM A. All the angles of any polygon, arc equal to twice as many right angles as there are sides less by four. Thus, 'all the angles At B, C, D, .£, F, G, arc equal to twice as many right angles as there... | |
 | John Dougall - 1810 - 554 pages
...two right angles, or two thirds of one right angle. PROP. VIII. fig. 21. The sum of all the interior angles of a polygon is equal to twice as many right angles, wanting four, as the figure has sides. Let the figure ABCDEF, be a polygon of six sides, that is, a... | |
 | Robert Gibson - Surveying - 1811 - 580 pages
...index, will give you the quantity of each respective angle. LEMMA. Att the angles of any polygon, are equal to twice as many right angles as there are sides less by four. Thus, all the angles A, B, C, D, £, f, G, are equal to twice as many right angles as there... | |
 | Robert Gibson - Surveying - 1814 - 558 pages
...will give you the quantity of each respective angle. JLEMMA. • ЛИ the angles of any polygon, are equal to twice as many right angles as there are sides less by four. Thus, all the angles Л, B, C, D, E, F, G, are equal to twice as many right anglet as there... | |
 | Charles William Hackley - Geometry - 1847 - 248 pages
...being equal to the same in another, the triangles are equal. THEOREM XVI. The sum of all the inward angles of a polygon is equal to twice as many right angles, wanting four, as the figure has sides. Let ABODE be any figure ; then the sum of all its inward angles,... | |
 | Elias Loomis - Conic sections - 1849 - 252 pages
...angles, or two thirds of one right angle. PROPOSITION XXVIII. THEOREM. The sum of all the interior angles of a polygon, is equal to twice as many right angles, wanting four, as the figure has sides. angles of each of these triangles, is equal to two right angles... | |
 | Frederick Overman - Building - 1851 - 452 pages
...the four internal angles of any quadrilateral figure is equal to four right angles. The sum of all the angles of a polygon is equal to twice as many right angles, less four, as the polygon has sides. The sum of the external angles of a polygon is equal to four right... | |
 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...the other part DAE is equal to the angle 0. PROPOSITTON XXVI. THEOEEM. The sum of oil the interior angles of a polygon, is equal to twice as many right angles, less four, as the figure has sides. A+B+C+D+fi be equal to twice .as many right angles, less four,... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...the other part DAE is equal to the angle C. PROPOSITION XXVI. THEOREM. The sum of all the interior angles of a polygon, is equal to twice as many right angles, less four, as the figure has sides. Let ABCDE be any polygon : then will the sum of its interior angles... | |
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Theorem. — The sum of all the angles of a polygon is equal to twice as many right angles as the polygon has sides, less two. 
