Practical Sheet Metal Work and Demonstrated Patterns: A Comprehensive Treatise, Volume 4John Henry Teschmacher David Williams Company, 1910 - Sheet-metal work |
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angle iron ball bead bolted bottom center line copper corner cornice corrugated iron cresting curve deck molding diagonal elevation dormer draw a line draw lines draw the line eave eleva elevation in Fig finial flashing front elevation half pattern hip and ridge hip ridge hip roll hipped roof holes horizontal lines inches length line traced lines drawn mansard roof method of fastening miter joint miter line nailed obtaining the patterns one-half parallel piece pipe pitch place the stretchout points thus obtained proceed as follows punched purlin radius RAFTER represent ridge pole ridge roll right angles riveted roof line screws seams sheet metal shown by similar shown in Fig shows side elevation side view sink strip small figures soldered spire take the distances terra cotta tile Trace a line vertical line wrought iron
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Page 124 - Fig. 310. Fig. 311. right angles to FD from points of intersection in the miter-lines DE and JF, as shown. Lines traced through points thus obtained, as shown by NOPR, will be the pattern for the raking moulding shown in plan, Fig. 307, by ABC Q'.
Page 123 - EF that of the roof, and GF the line of the pitched roof against which the dormer is required to miter. The front and side views being placed in their proper relative positions, the first step is to obtain a true section at right angles to EF. Proceed as follows: Divide the curve A to B into a number of equal spaces, as shown from 1 to 9. At right angles to AC, and from the figures on -AB, draw lines intersecting EG in side view as shown. From these intersections, and parallel to EF, draw lines intersecting...
Page 123 - Fig. 332. struck from the center points D, E, and F. A section taken on the line HJ in elevation is shown at the right; LM shows the roof of the dormer, indicated in the section by N; while the louvers are shown in elevation by OP and in section by RT. In Fig. 333 is shown how to obtain the various patterns for the various parts of the dormer. ABC represents the half-elevation of the dormer, and EFG a side view, of which EG is the line of the...
Page 124 - I2, 22, 32, etc., draw lines, which intersect with those of similar numbers drawn at right angles to CB, and from similarly numbered points on the curve A B. Trace a line through the points of intersection thus obtained. Then KLMJ will be one-half the...
Page 58 - ... to 7 on either side, from which points draw horizontal lines crossing HG in side view and intersecting the face HI of the bracket at points 1' to 7'. In line with HG, draw the line JK, upon which place the stretchout of the profile BCD, as shown by 1 to 7 to 7 to 1 on J K. At right angles to JK, draw the usual measuring lines as shown, which intersect by lines drawn parallel to JK from similarly numbered intersections on H I. Trace a line through the points thus obtained. Then ELEVATION will...
Page 124 - EH in side view, from which the stretchout will be obtained in the development of the pattern. For the pattern for the roof of the dormer, draw at right angles to EF in side view the line NO, upon which place the stretchout of one-half the true profile on the line EH as shown by the small figures I 4 , 2 4 , 3*, etc.
Page 124 - Z\Y, drawn at right angles to UV, as shown by the figures 1, 2, 3, etc. At right angles to UV, and from the figures, draw lines, which intersect with those of similar numbers drawn at right angles to YZ. B Through these points, trace a line.
Page 54 - ... to 13" on TU. Through these figures, at right angles to TU, draw lines as shown, which intersect by lines (not shown in the drawing) drawn at right angles to IH from similar points on the miter-lines HF and FI. Trace a line through the points thus obtained. Then will VWX be the...
Page 122 - ... inches. Having drawn the elevation and plan of the sphere, construct the plan of the prism as shown by ABC D. Parallel to the center line xy project the prism in elevation intersecting the sphere at a and c. Now since the center of the sphere is on one of the diagonals of the prism in plan, either two of the sides meeting at one end of that diagonal, as BC and CD, will be alike, and both will be different from the other two sides AB and AD, meeting at the opposite end of the diagonal. Therefore...
Page 99 - ... L1 M1, erect vertical lines intersecting similarly numbered horizontal lines drawn through the profile DE. Trace a line through the points thus obtained. Then will 1"— 13" be the true profile through No. 2 in plan at right angles to HI. For the pattern for No. 1 in plan, extend the line FK, as NO, upon which place the stretchout of the profile DE as shown by the figures 1 to 13 on NO. At right angles to NO, and from the figures, draw lines, which intersect with lines (partly shown) drawn parallel...