| Thomas Leybourn - Mathematics - 1814 - 420 pages
...Hence, by adopting the notation in the question, we have But the sum of the angles of any polygon being equal to twice as many right angles as the polygon has sides, less four; the sum of all the angles of the polygon will be equal to an even number of right angles, and consequently... | |
| John Radford Young - Euclid's Elements - 1827 - 228 pages
...to say, the sum of the angles of the polygon, together with those about the point within . it, are equal to twice as many right angles as the polygon has sides ; but those angles which are' about the point, amount to four right angles, (Prop. VI. Cor. 2.) deducting... | |
| Adrien Marie Legendre - Geometry - 1836 - 394 pages
...figure has sides, wanting four right angles. Hence, the interior angles plus four right .. -i angles, is equal to twice as many right angles as the polygon has aides, and consequently, equal to the sum of the interior angles plus the exterior angles. Taking from... | |
| Charles Reiner - Geometry - 1837 - 254 pages
...the angles about the common vertex of these triangles = 4 rt. /.s; therefore, the sum 01 the interior angles of any polygon is equal to twice as many right angles as the figure has sides less [minus] four. M.—If the number of sides be three, four, five, six, seven, &c.,... | |
| Charles Davies - Geometrical drawing - 1840 - 262 pages
...ACD, and ADE ; and the second, the similar triangles FHG, FBI, and F1K. 6. The sum of all the inward angles of any polygon is equal to twice as many right angles, wanting four, as the figure has sides. Thus, if the polygon has five sides, we have A + B + C+ D+E—W... | |
| Nathan Scholfield - 1845 - 894 pages
...of each as there arc sides of the polygon ; hence, the sum of all the interior and exterior angles is equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior angles is equal to two right angles, taken as many times, less two,... | |
| William Scott - Measurement - 1845 - 288 pages
...end ought to coincide. Also, the sum of all the angles, together with four right angles, ought to be equal to twice as many right angles as the polygon has sides (Eue. i. 32. cor.). To find the angle contained by two straight lines conceived to be drawn from a... | |
| Sir J. Butler Williams - Geodesy - 1846 - 368 pages
...of all the interior angles of the polygon formed by joining the stations by straight lines will be equal to twice as many right angles as the polygon has sides, wanting 4 right angles (Euc. Cor. 32, I.) Thus, if the figure have 3 sides, the sum of the interior... | |
| Charles Davies - Geometrical drawing - 1846 - 254 pages
...&c. 37. What is the sum of all the inward angles of a polygon equal to ? The sum of all the inward angles of any polygon is equal to twice as many right angles, wanting four, as the figure has sides. Thus, if the polygon has five sides, we have A + B+C+D + E=10... | |
| Anthony Nesbit - Plane trigonometry - 1847 - 492 pages
...check angle to prove the accuracy of the previous work. Moreover, since the sum of all the interior angles of any polygon is equal to twice as many right angles as the figure has sides, lessened by four ; as the given figure has five sides, the sum of all its interior... | |
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