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" A0, and the circumference which passes through the three points A, B, C, will also pass through the point D. By the same mode of reasoning, it may be shown that the circle which passes through the three vertices B, C, D, will also pass through the vertex... "
Tables of life contingencies - Page 15
by Griffith Davies - 1825 - 80 pages
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Tables of Life Contingencies: Containing the Rate of Mortality Among the ...

Griffith Davies - Life insurance - 1825 - 132 pages
...mortality in the former community would be to that of the latter as 100.265 is to 200.59, or as 1 to 2. By the same mode of reasoning it may be shown, that the decrements of life represented by Table i, in the succeeding intervals from 20 to 30, 30 to 40, &c., are to those expressed by Table x in the...
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Elements of Geometry and Trigonometry

Adrien Marie Legendre - Geometry - 1852 - 436 pages
...be greater than P. On the contrary, however, it is less : therefore, A 0 cannot be greater than AI. By the same mode of reasoning, it may be shown that the fourth term cannot be less than AI; therefore, it is equal to AI: hence, rectangular parallelopipedons...
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Elements of Geometry and Trigonometry from the Works of A.M. Legendre ...

Charles Davies - Geometry - 1854 - 436 pages
...be greater than P. On the contrary, however, it is less : therefore, AO cannot be greater than AI. By the same mode of reasoning, it may be shown that the fourth term cannot be less than AL; therefore, it is equal to AI: hence, rectangular parallelopipedons...
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Elements of Geometry and Trigonometry from the Works of A. M. Legendre ...

Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...be greater than P. On the contrary, however, it is less : therefore, A 0 cannot be greater than AI. By the same mode of reasoning, it may be shown that the fourth term cannot be less than AI; therefore, it is equal to AI: hence, rectangular parallelopipedons...
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Elements of Geometry and Trigonometry: With Practical Applications

Benjamin Greenleaf - Geometry - 1862 - 518 pages
...the circumference which passes through the three points A, B, C, will also pass through the point D. By the same mode of reasoning, it may be shown that the circle which passes through the three vertices B, C, D, will also pass through the vertex E, and so...
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Elements of Plane and Spherical Trigonometry: With Practical Applications

Benjamin Greenleaf - Geometry - 1861 - 638 pages
...which passes through the *• ' • '•• three points A, B, C, will also pass through the point D. By the same mode of reasoning, it may be shown that the circle which passes through the three vertices B, C, D, will also pass through the vertex E, and so...
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Elements of Geometry: With Practical Applications to Mensuration

Benjamin Greenleaf - Geometry - 1863 - 504 pages
...ference which passes through the v .' '. * three points A, B, C, will also puss through the point D. By the same mode of reasoning, it may be shown that the circle which passes through the three vertices B, C, D, will also pass through the vertex E, and so...
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Elements of Geometry: With Practical Applications to Mensuration

Benjamin Greenleaf - Geometry - 1868 - 340 pages
...the circumference which passes through the three points A, B, C, will also pass through the point D. By the same mode of reasoning, it may be shown that the circle which passes through the three vertices B, C, D, will also pass through the vertex E, and so...
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New Elementary Geometry: With Practical Applications ; a Shorter Course Upon ...

Benjamin Greenleaf - Geometry - 1873 - 202 pages
...the circumference which passes through the three points A, B, C, will also pass through the point D. By the same mode of reasoning, it may be shown that the circle which passes through the three vertices B, C, D, will also pass through the .vertex E, and so...
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New Elementary Geometry: With Practical Applications : a Shorter Course Upon ...

Benjamin Greenleaf - Geometry - 1874 - 206 pages
...consequently the- solid AG cannot be to the solid AL as the line AE is to a line greater than A I. BOOK V. By the same mode of reasoning, it may be shown that the fourth term of the proportion cannot be less than AI; therefore it must be equal to A I. Hence rectangular...
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