 | Jeremiah Day - Algebra - 1814 - 304 pages
...will be equal to , 2Q—X. Prob. 4. Divide 48 into two such parts, thafc if the less be divided by A and the greater by 6, the sum of the quotients will be 9. , Here if x be put for the smaller part, the greater will be48-*. x 48 — x By the conditions of the... | |
 | Jeremiah Day - Algebra - 1820 - 352 pages
...numbers be 20 And if one of them be represented by x The other will be equal to 20 — x. Prob. 4. Divide 48 into two such parts, that if the less be...greater by 6, the sum of the quotients will be 9. Here, if x be put for the smaller part, the greater will be 48— x. x 48— x By the conditions of... | |
 | Jeremiah Day - Algebra - 1827 - 352 pages
...two numbers be 20 And if one of them be represented by * The other will be equal to 20 - x. Prob. 4. Divide 48 into two such parts, that if the less be...greater by 6, the sum of the quotients will be 9. Here, if x be put for the smaller part, the greater will be 48— x. By the conditions of the problem-^—... | |
 | Jeremiah Day - Algebra - 1841 - 354 pages
...by x The other will be equal to 20 - x. Prob. 4. Divide 48 into two such parts, that if the less b« divided by 4, and the greater by 6, the sum of the quotients will be 9. Here, if x be put for the smaller part, the greater will b« 48-*. By the conditions of the problem... | |
 | James Bates Thomson - Algebra - 1844 - 272 pages
...that, The third has 600 less than one fourth of the whole ; What is the value of the estate 1 Prob. 4. Divide 48 into two such parts, that if the less be...greater by (6, the sum of the quotients will be 9. Let x = the smaller part. Then 48 — x = the greater part. By the conditions of the problem, - -f... | |
 | Horatio Nelson Robinson - Algebra - 1844 - 184 pages
...the unknown term stands. Many of the changes usually made, can as well be dispensed with. PROB. 8. Divide 48 into two such parts, that if the less be...greater by 6, the sum of the quotients will be 9. (D. 77.) Ans. 12 the less. Let z=the less ; then 48 — z=the greater. x , 48— x 4+~6-=9Multiply... | |
 | Horatio Nelson Robinson - Algebra - 1846 - 276 pages
...was equal to £ of the price of the chaise. What was the price of each? Ans. Chaise $120. Horse $80. 10. Divide 48 into two such parts, that if the less...quotients will be 9. Ans. 12 and 36. 11. An estate is to be divided among 4 children, in the following manner : The first is to have $200 more than 1... | |
 | James Bates Thomson - Algebra - 1846 - 276 pages
...whole ; What is the value of the estate 1 Prob. 4. Divide 48 into two such parts, that if the less he divided by 4, and the greater by 6, the sum of the quotients will he 9. Let x = the smaller part. Then 48- — a; = the greater part. rf* AQ /p By the conditions of... | |
 | Jeremiah Day - Algebra - 1847 - 358 pages
...two numbers be 20 And if one of them be represented by x The other will be equal to 20 - x. Prob. 4. Divide 48 into two such parts, that if the less be...greater by 6, the sum of the quotients will be 9. Here, if a; be put for the smaller part, the greater will be 48-*. By the conditions of the problem... | |
 | Jeremiah Day, James Bates Thomson - Algebra - 1848 - 264 pages
...that, The third has 600 less than one fourth of the whole ; What is the value of the estate 1 Prob. 4. Divide 48 into two such parts, that if the less be...greater by 6, the sum of the quotients will be 9. Let x -. the smaller part. Then 48 — x = the greater part. y, AU £1 By the conditions of the problem,... | |
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Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. Ans. 12 and 36. 11. An estate is to be divided among 4 children, in the following manner : The first is to have $200 more than 1... 
