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" SUBTRACT the less extreme from the greater, and divide the difference by 1 more than the number of means required to be found... "
A Course of Mathematics: Composed for the Use of the Royal Military Academy - Page 62
by Charles Hutton - 1860 - 895 pages
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A Course of Mathematics: For the Use of Academies as Well as Private Tuition

Charles Hutton - Mathematics - 1812 - 620 pages
...Ans. 9 the mean required. FBOBLEK PROBLEM V. Tofindttvo Arithmetical Means between Two Given Extremes. SUBTRACT the less extreme from the greater, and divide the difference by 3, so will the quotient be the common difference ; which being continually added to the less extreme,...
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A Course of Mathematics: In Two Volumes : for the Use of Academies ..., Volume 1

Charles Hutton - Mathematics - 1816 - 610 pages
...Given Terms or Extremes. SUBTR/VCT the less extreme from the greater, and divide the difference by I more than the number of means required to be found,...term, or subtracted from the greatest, will give the terms required. EXAMPLE. To find five arithmetical means between 2 and 14. Here 14 2 6)12 Then by adding...
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A Course of Mathematics: In Two Volumes. For the Use of Academies ..., Volume 1

Charles Hutton - Arithmetic - 1818 - 646 pages
...com. dif. 2 PROBLEM VI. To find any Number of Arithmetical Means between Toco Given Terms or Extremes. SUBTRACT the less extreme from the greater, and divide...term, or subtracted from the greatest, will give the terms required. EXAMPLE. To find five arithmetical means between 2 and 14. Here 14 6) 12 Then by adding...
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A Course of Mathematics: For the Use of Academies, as Well as Private ...

Charles Hutton - Mathematics - 1822 - 616 pages
...2) 18 Am. 9 the mean required. PROBLEM V. Tojind two Arithmetical Means between Two Given Extremes. SUBTRACT the less extreme from the greater, and divide the difference by 3, so will the quotient be the common difference ; which being continually added to the less extreme,...
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A Course of Mathematics: For the Use of Academies as Well as ..., Volume 1

Charles Hutton - Mathematics - 1831 - 632 pages
...Arithmetical Means between two given Terms or Extremes. SUBTRACT the less extreme from the greater, nnd divide the difference by 1 more than the number of...difference ; then this being added continually to the leust term, or subtracted from the greatest, will give the mean terms required. EXAMPLE. To find five...
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A New and Easy Introduction to the Mathematics: Containing. A system of ...

Ira Wanzer - Arithmetic - 1831 - 408 pages
...terms or extremes. RULE. — Subtract the Jess term or extreme from the greater ; divide the remainder by 1 more than the number of means required to be found; that is, divide by 2 for 1 mean, by 3 for 2 means, &c., and the quotient will be the common difference...
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Mental and Practical Arithmetic

Charles Davies - Arithmetic - 1838 - 292 pages
...EXAMPLES. 1. The extremes are 4 and 104, and the number of terms 26 : what is the common difference 1 We subtract the less extreme from the greater and divide the difference by one less tkan OPERATION. 104 426 — 1 = 25)100(4 the number of terms. Ans. 4. 2. A man has 8 sons,...
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Conversations on arithmetic

mrs. Henry Ayres - Arithmetic - 1843 - 470 pages
...CASE 4. — To find any number of arithmetical means between two given terms or extremes. liiilc. — Subtract the less extreme from the greater, and divide...difference by 1 more than the number of means required which will give the common difference; and this being added continually to the least term, or sub....
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The lady's practical arithmetician; or, Conversational arithmetic. [With] Key

mrs. Henry Ayres - 1846 - 400 pages
...CASE IV. — To find any number of Arithmetical means between two given terms or extremes. Rule. — Subtract the less extreme from the greater, and divide...difference by 1 more than the number of means required, which will give the common difference; and this being added continually to the least term, or subtracted...
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The University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - Arithmetic - 1846 - 370 pages
...the number of terms 26 : what is the common difference ? OPERATION. 104 4 26 — 1 = 25)100(4 100 We subtract the less extreme from the greater and divide the difference by one less than the number of terms. 2. A man has 8 sons, the youngest is 4 years old and the eldest...
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