A Course of Mathematics: Composed for the Use of the Royal Military Academy |
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Results 1-5 of 58
Page 269
... bisection of A B for the point equally illuminated by each light , a result which is manifestly true , upon the supposition that the intensity of the two lights is the same . a The other two values are reduced to that is , they become ...
... bisection of A B for the point equally illuminated by each light , a result which is manifestly true , upon the supposition that the intensity of the two lights is the same . a The other two values are reduced to that is , they become ...
Page 363
... bisected , or divided into two equal parts , by the line CD , making the angle ACD equal to the angle BCD . A D B Then , the two triangles ACD , BCD , have two sides and the contained angle of the one , equal to two sides and the ...
... bisected , or divided into two equal parts , by the line CD , making the angle ACD equal to the angle BCD . A D B Then , the two triangles ACD , BCD , have two sides and the contained angle of the one , equal to two sides and the ...
Page 365
... bisected in the point E , and draw the line AE , producing it till EF be equal to AE ; and join BF . = A B D Then , since the two triangles AEC , BEF , have the side AE the side EF , and the side CE = the side BE ( by suppos . ) , and ...
... bisected in the point E , and draw the line AE , producing it till EF be equal to AE ; and join BF . = A B D Then , since the two triangles AEC , BEF , have the side AE the side EF , and the side CE = the side BE ( by suppos . ) , and ...
Page 366
... bisected , it may be shown that the outward angle ABG , or its equal CBD , is greater than the other angle A. THEOREM IX . The greater side , of every triangle , is opposite to the greater angle ; and the greater angle opposite to the ...
... bisected , it may be shown that the outward angle ABG , or its equal CBD , is greater than the other angle A. THEOREM IX . The greater side , of every triangle , is opposite to the greater angle ; and the greater angle opposite to the ...
Page 378
... bisecting it into the two equal parts AD , DB ; then will the sum of the squares of AC , CB , be equal to twice the ... bisect each other ; and the sum of their squares is equal to the sum of the squares of all the four sides of the ...
... bisecting it into the two equal parts AD , DB ; then will the sum of the squares of AC , CB , be equal to twice the ... bisect each other ; and the sum of their squares is equal to the sum of the squares of all the four sides of the ...
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Other editions - View all
A Course of Mathematics: Composed for the Use of the Royal Military Academy Charles Hutton No preview available - 2015 |
A Course of Mathematics, Vol. 3: Composed for the Use of the Royal Military ... Charles Hutton No preview available - 2016 |
A Course of Mathematics, Vol. 3: Composed for the Use of the Royal Military ... Charles Hutton No preview available - 2018 |
Common terms and phrases
algebraic algebraic quantities axis binomial Binomial Theorem bisected centre circle circumference coefficient Completing the square contained Corol cosec cube root decimal degree denote diameter difference distance Divide dividend division divisor draw equal Example exponent expression extract factors feet figure fraction gives greater greatest common measure Hence inches least common multiple letters logarithm manner monomial multiplied negative nth root number of terms parallel parallelogram perfect square perpendicular plane polynomial positive Prob problem Prop proportional proposed equation quadratic quotient radical radius ratio rectangle reduce remainder result right angles rule second term sides sine square root straight line Substituting subtract tangent THEOREM triangle ABC unknown quantity VULGAR FRACTIONS Whence whole number yards
Popular passages
Page 332 - EC, have also the same altitude ; and because triangles of the same altitude are to each other as their bases, therefore the triangle ADE : BDE : : AD : DB, and triangle ADE : CDE : : AE : EC.
Page 352 - angle in a segment' is the angle contained by two straight lines drawn from any point in the circumference of the segment, to the extremities of the straight line which is the base of the segment.
Page 326 - Proportion, when the ratio is the same between every two adjacent terms, viz. when the first is to the second, as the second to the third, as the third to the fourth, as the fourth to the fifth, and so on, all in the same common ratio.
Page 17 - OF TIME. 60 Seconds = 1 Minute. 60 Minutes = 1 Hour. 24 Hours = 1 Day. 7 Days = 1 Week. 28 Days = 1 Lunar Month.
Page 338 - CD. conseconsequently the whole polygon, or all the triangles added together which compose it, is equal to the- rectangle of the common altitude CD, and the halves of all the sides, or the half perimeter of the polygon. Now, conceive the number of sides of the polygon to be indefinitely increased ; then will its perimeter coincide with the circumference of the circle, and consequently the altitude CD will become equal to the radius, and the whole polygon equal to the circle. Consequently the space...
Page 297 - The Height or Altitude of a figure is a perpendicular let fall from an angle, or its vertex, to the opposite side, called the base.
Page 26 - Multiply the number in the lowest denomination by the multiplier, and find how many units of the next higher denomination are contained in the product, setting down ,what remains.
Page 62 - From these theorems may readily be found any one of these five parts ; the two extremes, the number of terms, the common difference, and the sum of all the terms, when any three of them are given, as in the following Problems : PROBLEM I.
Page 326 - Proportional, when the ratio of the first to the second, is equal to the ratio of the second to the third.
Page 62 - SUBTRACT the less extreme from the greater, and divide the difference by 1 more than the number of means required to be found...