 It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of the first term.  A School Algebra - Page 255by George Albert Wentworth - 1891 - 362 pagesFull view - About this book
 | William Frothingham Bradbury - Algebra - 1868 - 264 pages
...completed without multiplying the equation, by adding to both members the square of the quotient arising from dividing the second term by twice the square root of the first. This method also becomes the same as the first method when the coefficient of z2 is unity. NOTE 3.... | |
 | William Frothingham Bradbury - Algebra - 1877 - 302 pages
...completed without multiplying the equation, by adding to both members the square of the quotient arising from dividing the second term by twice the square root of the first. This method also becomes the same as the first method when the coefficient of 3? is unity. NOTE 3.... | |
 | George Albert Wentworth - Algebra - 1881 - 400 pages
...square ; that is, to add to each side the square of the quotient obtained from dividing the second tei'm by twice the square root of the first term. The second...equation. The third and last step is to reduce the resulting simple equation. (1) Solve the equation 16 ^ + 5 x — 3 = 7^ — x + 45. Simplify, 9x2 +... | |
 | George Albert Wentworth - Algebra - 1885 - 548 pages
...lacks only the ¿Лzrrf term, b2, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root ofthefirst term. 226. Every affected quadratic may be made to assume the form of а?a? ± 2 abx = c.... | |
 | Webster Wells - Algebra - 1885 - 370 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9яr — 5ж= 4. The quotient of the second term divided by twice the square... | |
 | Webster Wells - 1885 - 368 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9 ar — 5 ж = 4. The quotient of the second term divided by twice the 5 5 square... | |
 | Webster Wells - Algebra - 1885 - 382 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9 яr — 5 ж = 4. The quotient of the second term divided by twice the 5 5... | |
 | George Albert Wentworth - Algebra - 1886 - 284 pages
...abx lacks only the third term, V, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of thefirst term. 218. Every affected quadratic may he made to assume the form of a?x2 ± 2 abx = c. The... | |
 | George Albert Wentworth - Algebra - 1887 - 268 pages
...abx lacks only the third term, b\ of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing...second term by twice the square root of the first term. 218. Every affected quadratic may be made to assume the form of aV ± 2 abx = c. The first step in... | |
 | George Albert Wentworth - Algebra - 1888 - 518 pages
...lacks only the ¿Am¿ term, Js, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of t he first term. 226. Every affected quadratic may be made to assume the form of aV i 2 abx = c. The... | |
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