Elements of Geometry and Trigonometry: From the Works of A. M. Legendre |
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Page 4
... examples . Babies ' Bourdon's Algebra - Including Sturm's and Horner's Theorems , and practical examples . Babies ' Legendre's Geometry and Trigonometry - Revised and adapted to the course of Mathematical Instruction in the United ...
... examples . Babies ' Bourdon's Algebra - Including Sturm's and Horner's Theorems , and practical examples . Babies ' Legendre's Geometry and Trigonometry - Revised and adapted to the course of Mathematical Instruction in the United ...
Page 26
... example , there will remain ( A. 5 ) , AC – BC < AB` ; as BC , for that is , the difference between any two sides of a triangle is Less than the third side . Scholium . In order that any three given lines may re present the sides of a ...
... example , there will remain ( A. 5 ) , AC – BC < AB` ; as BC , for that is , the difference between any two sides of a triangle is Less than the third side . Scholium . In order that any three given lines may re present the sides of a ...
Page 74
... example , that this unit is contained 7 times in the angle ACB , and 4 times in the angle DOE ACB be divided into 7 angles , by the radii & c .; and DOE into 4 angles , by the radii Oz , each equal to the unit M. Then , suppose Cm , Cn ...
... example , that this unit is contained 7 times in the angle ACB , and 4 times in the angle DOE ACB be divided into 7 angles , by the radii & c .; and DOE into 4 angles , by the radii Oz , each equal to the unit M. Then , suppose Cm , Cn ...
Page 193
... example , that AE is to AI , as 15 is to 8 . Conceive AE to be which AI will contain 8 ; divided into 15 equal parts , of through the points of division These planes will let planes be passed parallel to ABCD . divide the ...
... example , that AE is to AI , as 15 is to 8 . Conceive AE to be which AI will contain 8 ; divided into 15 equal parts , of through the points of division These planes will let planes be passed parallel to ABCD . divide the ...
Page 252
... example , let them be to each other as 5 is to 48. Divide the circumference MNPQ into 48 equal parts , be- ginning at M ; MN will contain five of these parts . Join each point MK Z of division with the points A and B , by a quadrant ...
... example , let them be to each other as 5 is to 48. Divide the circumference MNPQ into 48 equal parts , be- ginning at M ; MN will contain five of these parts . Join each point MK Z of division with the points A and B , by a quadrant ...
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Common terms and phrases
AB² ABCD altitude apothem Applying logarithms centre chord circle circumference cone consequently convex surface cosec Cosine Cotang cylinder demonstrated in Book denote diameter distance divided draw edges Equation feet find the area Find the logarithmic following RULE frustum given angle greater hence homologous hypothenuse included angle inscribed intersection less Let ABC linear units log cot log sin lower base lune mantissa multiplied number of sides opposite parallel parallelogram parallelopipedon perpendicular plane MN polar triangle polyedral angle polyedron principle demonstrated prism proportional PROPOSITION proved pyramid quadrant radii radius rectangle regular polygon right angles right-angled triangle Scholium segment similar six right slant height solution sphere spherical angle spherical excess spherical polygon spherical triangle square straight line subtracting Tang tangent THEOREM triangle ABC triangular prism upper base vertex volume whence write the following