| Adrien Marie Legendre - Geometry - 1819 - 208 pages
...of Us base by its altitude. Demonstration. The parallelogram ABCD (fig. 97) is equip- Fig. 97. alent **to the rectangle ABEF, which has the same base AB and the same altitude** BE (167) : but this last has for its measure JlB x BE (173) ; therefore. AB x BB is equal to the area... | |
| Adrien Marie Legendre - Geometry - 1822 - 367 pages
...to the product of Its base by its altitude. For the parallelogram ABCD is equivalent (I. III. Cor.) **to the rectangle ABEF, which has the same base AB, and the same altitude** BE: but this rectangle (4. III. Schol.) is measured by ABx BE; therefore ABx BE is equal to the area... | |
| Adrien Marie Legendre - Geometry - 1825 - 224 pages
...of its base by its altitude. Demonstration. The parallelogram ABCD (Jig. 97) is equiva-Fig. 37. lent **to the rectangle ABEF, which has the same base AB and the same altitude** BE (167); but this last has for its measure AB x BE (173) ; therefore AB x BE is equal to the area... | |
| Adrien Marie Legendre - Geometry - 1836 - 359 pages
...equal to the product of its bast by its altitude. For, the parallelogram ABCD is equivalent PJD EC **to the rectangle ABEF, which has the same base AB, and the same altitude** BE (Prop. I. Cor.) : but this rectangle is measured by AB x BE (Prop. IV. Sch.) ; therefore, AB x BE... | |
| Adrien Marie Legendre - Geometry - 1838 - 359 pages
...equal to the product of its base by its altitude. For, the parallelogram ABCD is equivalent jF D EC o **the rectangle ABEF, which has the same base AB, and the same altitude** BE (Prop. I. Cor.) : but this rectangle is measured by AB xBE (Prop. IV. Sch.); therefore, AB x BE... | |
| James Bates Thomson - Geometry - 1844 - 237 pages
...to the product of its base AB by its altitude BE. For the parallelogram ABCD is equivI* D EC alent **to the rectangle ABEF, which has ...... the same base AB, and the same altitude** BE; (1.4. Cor.;) but this rectangle is measured by AB x BE ; (4. 4. -^ Sch. ;) therefore AB x BE is... | |
| Nicholas Tillinghast - Geometry, Plane - 1844 - 96 pages
...parallelogram is equivalent to a rectangle which has an equal base and equal altitude. Cor. 2. Hence **the area of a parallelogram is equal to the product of its** base by its altitude (Prop. 1).* Cor. 3. Hence parallelograms of equal altitudes, are in proportion... | |
| Nathan Scholfield - 1845
...is equal to the product of its base by its altitude. FD EC For, the parallelogram ABCD is equivalent **to the rectangle ABEF, which has the same base AB, and the same altitude** «K (Prop. 111. Cor.) : but this rectangle is measured by ABxBE (Prop. VI. Sch.) ; therefore, ABXBB... | |
| Charles Davies - Trigonometry - 1849 - 384 pages
...equal to the product of its base by its altitude. For, the parallelogram ABCD is equivalent ff ~fi EC **to the rectangle ABEF, which has the same base AB, and the same altitude** BE (Prop. I. Cor.): but this rectangle is measured by AB x BE (Prop. IV. Sch.); therefore, AB x BE... | |
| Elias Loomis - Conic sections - 1849 - 252 pages
...the base, and the other the number of linear units contained in the altitude. PROPOSITION V. THEOREM. **The area of a parallelogram is equal to the product of its** base by its altitude. Cor. Parallelograms of the same base are to each other as their altitudes, and... | |
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