 | Adrien Marie Legendre - Geometry - 1819 - 574 pages
...of Us base by its altitude. Demonstration. The parallelogram ABCD (fig. 97) is equip- Fig. 97. alent to the rectangle ABEF, which has the same base AB and the same altitude BE (167) : but this last has for its measure JlB x BE (173) ; therefore. AB x BB is equal to the area... | |
 | Adrien Marie Legendre - Geometry - 1822 - 394 pages
...to the product of Its base by its altitude. For the parallelogram ABCD is equivalent (I. III. Cor.) to the rectangle ABEF, which has the same base AB, and the same altitude BE: but this rectangle (4. III. Schol.) is measured by ABx BE; therefore ABx BE is equal to the area... | |
 | Adrien Marie Legendre, John Farrar - Geometry - 1825 - 294 pages
...of its base by its altitude. Demonstration. The parallelogram ABCD (Jig. 97) is equiva-Fig. 37. lent to the rectangle ABEF, which has the same base AB and the same altitude BE (167); but this last has for its measure AB x BE (173) ; therefore AB x BE is equal to the area... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...equal to the product of its bast by its altitude. For, the parallelogram ABCD is equivalent PJD EC to the rectangle ABEF, which has the same base AB, and the same altitude BE (Prop. I. Cor.) : but this rectangle is measured by AB x BE (Prop. IV. Sch.) ; therefore, AB x BE... | |
 | Adrien Marie Legendre - Geometry - 1838 - 382 pages
...equal to the product of its base by its altitude. For, the parallelogram ABCD is equivalent jF D EC o the rectangle ABEF, which has the same base AB, and the same altitude BE (Prop. I. Cor.) : but this rectangle is measured by AB xBE (Prop. IV. Sch.); therefore, AB x BE... | |
 | James Bates Thomson - Geometry - 1844 - 268 pages
...to the product of its base AB by its altitude BE. For the parallelogram ABCD is equivI* D EC alent to the rectangle ABEF, which has ...... the same base AB, and the same altitude BE; (1.4. Cor.;) but this rectangle is measured by AB x BE ; (4. 4. -^ Sch. ;) therefore AB x BE is... | |
 | Nicholas Tillinghast - Geometry, Plane - 1844 - 108 pages
...parallelogram is equivalent to a rectangle which has an equal base and equal altitude. Cor. 2. Hence the area of a parallelogram is equal to the product of its base by its altitude (Prop. 1).* Cor. 3. Hence parallelograms of equal altitudes, are in proportion... | |
 | Nathan Scholfield - 1845 - 894 pages
...is equal to the product of its base by its altitude. FD EC For, the parallelogram ABCD is equivalent to the rectangle ABEF, which has the same base AB, and the same altitude «K (Prop. 111. Cor.) : but this rectangle is measured by ABxBE (Prop. VI. Sch.) ; therefore, ABXBB... | |
 | Charles Davies - Trigonometry - 1849 - 372 pages
...equal to the product of its base by its altitude. For, the parallelogram ABCD is equivalent ff ~fi EC to the rectangle ABEF, which has the same base AB, and the same altitude BE (Prop. I. Cor.): but this rectangle is measured by AB x BE (Prop. IV. Sch.); therefore, AB x BE... | |
 | Elias Loomis - Conic sections - 1849 - 252 pages
...the base, and the other the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Cor. Parallelograms of the same base are to each other as their altitudes, and... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
