 Prove that the middle point of the hypotenuse of a right triangle is equidistant from the three vertices.  Analytic Geometry - Page 32by Lewis Parker Siceloff, George Wentworth, David Eugene Smith - 1922 - 290 pagesFull view - About this book
 | George Albert Wentworth - Geometry, Analytic - 1886 - 346 pages
...one end of the line is (5, 7). What are the coordinates of the other end ? 7. Prove that the middle point of the hypotenuse of a right triangle is equidistant from the three vertices. 8. Prove that the diagonals of a parallelogram mutually bisect each other. 9. Show that the values... | |
 | George Albert Wentworth - 1886 - 322 pages
...of the line is (5, 7). What are the coordinates of the other end ? 7. Prove that the middle poiiit of the hypotenuse of a right triangle is equidistant from the three vertices. 8. Prove that the diagonals of a parallelogram mutually bisect each other. 9. Show that the values... | |
 | George Albert Wentworth, George Anthony Hill - Geometry - 1894 - 150 pages
...that the bisectors of the angles of a triangle meet in one point (155, 156). 4. Prove that the middle point of the hypotenuse of a right triangle is equidistant from the three vertices. (Hint: Draw a perpendicular from the middle point to one leg. 127,164,145.) Propositions 161, 163.... | |
 | John Henry Tanner, Joseph Allen - Geometry, Analytic - 1898 - 458 pages
...point (f, 0) is equidistant from (-1, 1), (1, 2), and (1, -2). 13. Prove analytically that the middle point of the hypotenuse of a right triangle is equidistant from the three vertices. 14. Three vertices of a parallelogram are (1, 2), (— 5,— 3), and (7, — 6) ; what is the fourth... | |
 | George Albert Wentworth - Geometry - 1899 - 498 pages
...§128 §139 Hyp. §93 §110 BOOK I. PLANE GEOMETRY. Prove by the synthetic method : Ex. 21. The middle point of the hypotenuse of a right triangle is equidistant from the three vertices. From D, the middle point, draw DE _L to CB. DE is II to AC (why ?), and DE bisects CB (why ?). .-.... | |
 | George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...if A But A CGE = A ADE. For EC = AE. /.GEC -/.AED. Prove by the synthetic method: Ex. 21. The middle point of the hypotenuse of a right triangle is equidistant from the three vertices. From D, the middle point, draw DE ± to CB. DE is II to AC (why ?), and DE bisects CB (why ?). .'.... | |
 | George Albert Wentworth, George Anthony Hill - Geometry - 1901 - 174 pages
...lettered. THEOREMS 1. The sum of the acute angles of a right triangle is equal to 9O°. 2. The middle point of the hypotenuse of a right triangle is equidistant from the three vertices of the triangle. 3. The angles opposite the equal sides of an isosceles triangle are equal. 4. If two... | |
 | Percey Franklyn Smith, Arthur Sullivan Gale - Geometry, Analytic - 1904 - 453 pages
...the line joining the points (- 2, - 1) and (3, 2). Ans. (- |, 0), (f, 1). 9. Prove that the middle point of the hypotenuse of a right triangle is equidistant from the three vertices. 10. Show that the diagonals of the parallelogram whose vertices are (1, 2), (-5, - 3), (7, - 6), (1,... | |
 | George Albert Wentworth - Geometry - 1904 - 496 pages
...For .EC = 4.E. ZGEC = BOOK I. PLANE GEOMETRY. E B Prove by the synthetic method : Ex. 21. The middle point of the hypotenuse of a right triangle is equidistant from the three vertices. From D, the middle point, draw DM JL to CB. DE is \\loAC (why ?), and DE bisects CB (why ?). .-. D... | |
 | Percey Franklyn Smith, Arthur Sullivan Gale - Geometry, Analytic - 1904 - 462 pages
...the line joining the points (-2, - 1) and (3, 2). Ans. (- ¿, 0), (;}, 1). 9. Prove that the middle point of the hypotenuse of a right triangle is equidistant from the three vertices. 10. Show that the diagonals of the parallelogram whose vertices are (I, 2), (- 5, - 3), (7, - 6), (1,... | |
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