 | John Radford Young - Astronomy - 1833 - 286 pages
...value given by (3, p. 77), viz. sin. a sin. C ; sin.c=; : — - — : am. A ' and it becomes „ sin. a sin. C cos. A cos. a sin. b = sin. a cos. b cos. C as : sin, A that is, dividing by sin. a, • cot. a sin. = cos. l> cos. C .f- sin. C cot. A ; which... | |
 | John Radford Young - Astronomy - 1833 - 308 pages
...-fsin. Ь ein. с cos. A ; or, cancelling cos. a on each side, dividing by sin.t, and transposing, cos. a sin. b = sin. a cos. b cos. C + sin. c cos. A .... (1). For sin. c in this equation substitute its value given by (3, p. 77), viz. sin. a sin.... | |
 | Christoph Gudermann - Geometry - 1835 - 406 pages
...a. cos B = cos b sin a — sin b cos с cos A, sin a. cos С = cos с sin b — sin с cos b cos A, sin c. cos A = cos a sin b — sin a cos b cos C, sin c. cos B = cos b sin a — sin b cos a cos C. §. 128. îebrfaÇj. £er <5iituö cinco üBinfcío muítiplict'rt... | |
 | John Charles Snowball - 1837 - 322 pages
...sin C . cos a (iii.) Whence, cos A + cos В . cos C cosa = sin В . sin C 30. То shew that Sin с . cos A = cos a . sin b — sin a . cos b . cos C. By (ii), cos с = cos a . cos b + sin a . sin b . cos C. So also, sin b . sin с . cos A = cos a —... | |
 | Nathan Scholfield - Geometry - 1845 - 506 pages
...sin. b — sin. a cos. b cos. C But, sin. C . , Sin" C=" sTnTA Sm< a> y (6)) .-. cos. A . ' . sin. a— cos. a sin. b — sin. a cos. b cos C sin. A cot. A=cot. a sin. b cosec. C— cos. b cot. C. In which the cotangent of A is expressed in the required... | |
 | Nathan Scholfield - Conic sections - 1845 - 542 pages
...a cos. b cos. C But, sin. C . sin. c= - — T sin. a, by (s), sin. A sin. C . .•. cos. A T- sin. a— cos. a sin. b — sin. a cos. b cos C sin. A cot. A=cot. a sin. b cosec. C— cos. I cot. C. In which the cotangent of A is expressed in the required... | |
 | John Radford Young - Geometry, Solid - 1848 - 384 pages
...Napier, and are known by the name of Napier's Analogies. By the equation (1), page 50, we have sin. с cos. A = cos. a sin. b — sin. a cos. b cos. C. Similarly, sin. с cos. В = cos, b sin, a — sin, 4 cos, a cos. С .-. sin. с (cos. A -f- cos. B)... | |
 | Adam von Burg - Mathematics - 1851 - 684 pages
...lz) — sin a sin b cos b cos C, also wenn man (da l — cos b* = sin b* ist) durch sin b abkürzt: cos A = (cos a sin b — sin a cos b cos C) : sin c, oder endlich , wegen sin c = sin a sin C : sin A, auch : cot A sin C -\- cos b cos C=cota sin b ; um... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...= cos. C sin. A + sin. C cos. A cos. & ; I sin. B cos. a = co&. A sin. C + sin. A cos. C cos. I. I sin. C cos. a — cos. A sin. B + sin. A cos. B cos. c ; \ sin. C cos. Z» = cos. B sin. A + sin. B cos. A cos. c. (J.) CHAPTEK YI. SOLUTION OF SPHERICAL EIGHT TRIAKGLES.... | |
 | Adam ritter von Burg - 1859 - 708 pages
...&2) — sin a sin b cos b cos C, also wenn man (da l — cos bz = sin b2 ist) durch sin b abkürzt : cos A = (cos a sin b — sin a cos b cos C) : sin c, oder endlich, wegen sin c = sin a sin C: sin A, auch: cot A sin C + cos b cos C = cot a sin b ; um... | |
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C cos. b. sin. C cos. a = cos. A sin. B + sin. A cos. B cos. c ; sin. C cos. 
