An Elementary Treatise on Plane & Spherical Trigonometry: With Their Applications to Navigation, Surveying, Heights, and Distances, and Spherical Astronomy, and Particularly Adapted to Explaining the Construction of Bowditch's Navigator, and the Nautical Almanac |
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Page 16
... give the proportion BC : BB ' = CP : B'R . But , by $ 22 , BB ' sin . m . Hence 1 sin . m cos . M : B'R ; and B'R sin . m . cos . M , which gives , by substitution , sin . ( M + m ) : = sin , M + sin . m . cos . M. ( 17 ) Cosine of an ...
... give the proportion BC : BB ' = CP : B'R . But , by $ 22 , BB ' sin . m . Hence 1 sin . m cos . M : B'R ; and B'R sin . m . cos . M , which gives , by substitution , sin . ( M + m ) : = sin , M + sin . m . cos . M. ( 17 ) Cosine of an ...
Page 20
... gives a = h sin . A ; or , by logarithms , log . a = log . h + log . sin . A. Thirdly . To find the side b , we have by ( 4 ) b cos . A h ' which , multiplied by h , gives or , by logarithms , bh cos . A ; log.blog.h + log . cos . A ...
... gives a = h sin . A ; or , by logarithms , log . a = log . h + log . sin . A. Thirdly . To find the side b , we have by ( 4 ) b cos . A h ' which , multiplied by h , gives or , by logarithms , bh cos . A ; log.blog.h + log . cos . A ...
Page 21
... gives by ( 6 ) a h = a cosec . A ; ( 23 ) sin . A or , by logarithms , log . h = log . a + ( ar . co . ) log . sin . A = log . a + log . cosec . A. Thirdly . To find the other leg b , we have by ( 4 ) b cotan . A which , multiplied by a ...
... gives by ( 6 ) a h = a cosec . A ; ( 23 ) sin . A or , by logarithms , log . h = log . a + ( ar . co . ) log . sin . A = log . a + log . cosec . A. Thirdly . To find the other leg b , we have by ( 4 ) b cotan . A which , multiplied by a ...
Page 22
... gives whence a2 + b2 = h2 , b2 = h2 — a2 = ( h + a ) ( h — a ) , - ( 28 ) b = √ ( h2 — - a2 ) = √ [ ( h + a ) ( h — a ) ] ; ( 29 ) by logarithms , log . b . = log . ( h2— a2 ) = 1⁄2 [ log . ( h + a ) + log . ( h — a ) ] . 36. Problem ...
... gives whence a2 + b2 = h2 , b2 = h2 — a2 = ( h + a ) ( h — a ) , - ( 28 ) b = √ ( h2 — - a2 ) = √ [ ( h + a ) ( h — a ) ] ; ( 29 ) by logarithms , log . b . = log . ( h2— a2 ) = 1⁄2 [ log . ( h + a ) + log . ( h — a ) ] . 36. Problem ...
Page 30
... give the propor- tion AB ' : BB ' — B'C : B'P , or h ' : + a ' = a ' : z ; whence z = a a ' + a12 h ' and y = h ' z = h ' a a ' + a12 h ' - h / 2 a / 2 - a a ' h ' But , from the right triangle ABC , h / 2 a2 = whence ( AB ' ) 2 — ( B'C ) ...
... give the propor- tion AB ' : BB ' — B'C : B'P , or h ' : + a ' = a ' : z ; whence z = a a ' + a12 h ' and y = h ' z = h ' a a ' + a12 h ' - h / 2 a / 2 - a a ' h ' But , from the right triangle ABC , h / 2 a2 = whence ( AB ' ) 2 — ( B'C ) ...
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Common terms and phrases
A₁ aberration altitude and azimuth angle given ascension and declination azimuth celestial equator celestial sphere centre circle computed Corollary corr correct central altitude corresponding cosec cosine cotan diff difference of latitude difference of longitude dist earth eclipse of April equal to 90 formula gives Greenwich Hence horizon horizontal parallax hour angle hypothenuse included angle interval latitude and longitude lunar distance mean meridian altitude method middle latitude moon's motion N₁ Napier's Rules Nautical Almanac Navigator Nutation obliquity obtuse perpendicular plane polar triangle prime vertical Problem R₁ radius reduced right ascension sailing Scholium second member semidiameter sideral sideral day solar eclipse Solution solve the triangle spherical right triangle spherical triangle star's sun's Table XXIII tang tangent Theorem transit triangle ABC Trig true latitude tude vernal equinox whence
Popular passages
Page 156 - I. The sine of the middle part is equal to the product of the tangents of the adjacent parts.
Page 145 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Page 48 - As the sine of the angle opposite the given side is to the sine of the angle opposite the required side, so is the given side to the required side. Thus, if a (fig.
Page 50 - The third side is found by the proportion. As the sine of the given angle is to the sine of the angle opposite the required side, so is the side opposite the given angle to the required side.
Page 41 - Since, when an angle is acute its supplement is obtuse, it follows from the preceding proposition, that the sine and cosecant of an obtuse angle are positive, while its cosine, tangent, cotangent, and secant, are negative.
Page 53 - The sum of any two sides of a triangle is to their difference, as the tangent of half the sum of the angles opposite to those sides, to the tangent of half their difference.
Page 182 - But a' = 180° - A, b' = 180° - ß, c' = 180° - C. and A' = 180° - a. Therefore, — cos A = (— cos B)(— cos C) + sin B sin C(— cos a...