| Robert Simson - Trigonometry - 1762 - 488 pages
...the fame reafon CF is equal to FD. and becaufe AD is equal to BC, and AF to FB, the two fides FA, AD are equal to the two FB, BC, each to each ; and the bafe DF was proved equal to the bafe FC ; therefore the angle FAD is eeq'.ial d to the angle FBC. agam,... | |
| Euclid - 1781 - 552 pages
...fame reafon, CF is equal to FD : And becaufe AI? is equal to BC, and AF to FB, the two fides FA, AD are equal to the two FB, BC, each to each ; and the bafe DF was proved equal to the bafe FC ; therefore the angle FAD is equal d to the angle FBC : Again,... | |
| Euclid, John Playfair - Euclid's Elements - 1795 - 462 pages
...and the whole angle DBA is equal e to til whole FBC ; and becaufe the two fides AB, BD are equal tt the two FB, BC, each to each, and the angle DBA equal th the angle FBC ; therefore the bafe AD is equal f to the bafe Book I. FC, and the triangle \BD to... | |
| Alexander Ingram - Trigonometry - 1799 - 374 pages
...angle ARC, e s. Ax. and tne whole angle DBA is equal e to the whole FBC ; and becaufe the two fides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; f 4. i. therefore the bafe AD is equal i to the bafe FC, and the triangle ABD to the triangle FBC... | |
| John Playfair, Euclid - Circle-squaring - 1804 - 468 pages
...each the angle ABC, the whole angle DBA will be equal e to the whole FBC ; and becaufe the two fides AB, BD, are equal to the two FB, BC, each to each, and the angle DBA equal to tho the angle FBC, therefors the bafe AD is equal f te the bafe Book I. FC, and the triangle ABD to... | |
| Robert Simson - Trigonometry - 1804 - 530 pages
...the fame reafon CF is equal to FD. and becaufe AD is equal to BC, and AF to FB, the two fides FA, AD are equal to the two FB, BC, each to each; and the bafe DF was proved equal to the bafe FC ; therefore the angle FAD is equal d to the angle FBC. again,... | |
| Euclid - Geometry - 1810 - 554 pages
...FBA, each of them being a right angle, add to each the angle ABC, and the whole angle DBA is tqual« to the whole FBC ; and because the two sides AB, BD are equal to the two FB, BC,1 each to each, and the angle DBA equal to the angle FBC ; therefore the base AD is equal f to the... | |
| John Playfair - Circle-squaring - 1819 - 350 pages
...them being a right angle, -adding to each the angle ABC, the whole angle DBA will be equal (2. Ax.) to the whole FBC ; and because the two sides AB, BD,...are equal to the two FB, BC each 'to each, and the ans;le DBA eqnal to the angle FBC, therefore the base AD is equal (4. 1.) to the base FC, and the triangle... | |
| John Playfair - 1819 - 354 pages
...them being a right angle, adding to each the angle ABC, the whole angle DBA will be equal (2. A\.) to the whole FBC ; and because the two sides AB, BD, are equa! to the two FB, BC each to each, and the angle DBA equal to thr> angle FBC, therefore the base... | |
| Euclid, John Playfair - Euclid's Elements - 1826 - 326 pages
...adding to eaeh the angle ABC, the whole augif DBA will be equal (2. Ax.) to the whole FBC ; and beeause the two sides AB. BD, are equal to the two FB, BC eaeh, to eaeh and the angle DBA equal to the II angle FBC, therefore the base AD is equal (4, 1.) to... | |
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