## The Elements of Euclid, books i. to vi., with deductions, appendices and historical notes, by J.S. Mackay. [With] Key1884 |

### From inside the book

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**inscribed*** in a given || m intersect one another at the same point . 60. In a given rhombus**inscribe**a square . 61. In a given right - angled isosceles triangle**inscribe**a square . 62. In a given square**inscribe**an equilateral triangle ... Page 190

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**inscribed**in a circle are supplementary . Conversely : If the opposite angles of a quadrilateral be supplementary , a circle may be circumscribed about the quadrilateral . * B A G B ( 1 ) Let the quadrilateral ABCD be**inscribed**in the ... Page 191

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**inscribed**in a circle be produced , the exterior angle is equal to the remote interior angle of the quadrilateral . For each is supplementary to the interior adjacent angle . I. 13 , III . 22 1. If a m be**inscribed**in a circle , it must ... Page 196

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**inscribed**in a circle be equal , the diagonal which does not join their vertices is a diameter of the circle . 4. Any segment of a circle containing a right angle is a semicircle . 5. Any segment of a circle containing an acute angle is ... Page 202

Euclides John Sturgeon Mackay. E ( 3 ) Because ABCD is a quadrilateral

Euclides John Sturgeon Mackay. E ( 3 ) Because ABCD is a quadrilateral

**inscribed**in the circle , : . L B + LD = two rt . 4 s . But B is less than a rt . ; ... LD is greater than a rt . . III . 22 1. Circles described on the equal sides ...### Other editions - View all

### Common terms and phrases

ABē ABCD ACē ADē angles equal base BC bisected bisector CDē centre chord circumscribed Const deduction diagonals diameter divided in medial divided internally draw equiangular equilateral triangle equimultiples Euclid's exterior angles Find the locus given circle given point given straight line greater Hence hypotenuse inscribed intersection isosceles triangle less Let ABC lines is equal magnitudes medial section median meet middle points opposite sides orthocentre parallel parallelogram perpendicular polygon produced PROPOSITION 13 Prove the proposition quadrilateral radical axis radii radius ratio rectangle contained rectilineal figure regular pentagon required to prove rhombus right angle right-angled triangle square on half straight line drawn straight line joining tangent THEOREM unequal segments vertex vertical angle Нур

### Popular passages

Page 147 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.

Page 276 - IF there be any number of magnitudes, and as many others, which, taken two and two, in a cross order, have the same ratio; the first shall have to the last of the first magnitudes the same ratio which the first of the others has to the last. NB This is usually cited by the words

Page 331 - If the vertical angle of a triangle be bisected by a straight line which also cuts the base, the segments of the base shall have the same ratio which the other sides of the triangle have to one another...

Page 17 - From the greater of two given straight lines to cut off a part equal to the less. Let AB and C be the two given straight lines, whereof AB is the greater.

Page 112 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.

Page 87 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.

Page 254 - If there be four magnitudes, and if any equimultiples whatsoever be taken of the first and third, and any equimultiples whatsoever of the second and fourth, and if, according as the multiple of the first is greater than the multiple of the second, equal to it or less, the multiple of the third is also greater than the multiple of the fourth, equal to it or less ; then, the first of the magnitudes is said to have to the second the same ratio that the third has to the fourth.

Page 138 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.

Page 304 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Page 44 - America, but know that we are alive, that two and two make four, and that the sum of any two sides of a triangle is greater than the third side.