| Adrien Marie Legendre - Geometry - 1819 - 574 pages
...(291), and the solidity of the cylinder will be rR*xH, or »/?*//. MMMA. 520. The convex surface of a **right prism is equal to the perimeter of its base multiplied by its altitude.** Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (j%. 25S),... | |
| Adrien Marie Legendre - Geometry - 1822 - 394 pages
...solidity of the cylinder will be a-R2 x M, or a-R2 H. PROPOSITION II. LEMMA. The convex surface of a **right prism is equal to the perimeter of its base multiplied by its altitude.** For this surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c, (see fig. of Def. 5.)... | |
| Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...(291), and the solidity of the cylinder will be n R' x H, or nR'H. LEMMA. 520. The convex surface of a **right prism is equal to the perimeter of its base multiplied by its altitude.** Now the altitudes AF, BG, CH, &c., of these rectangles are each equal to the altitude of the prism.... | |
| Adrien Marie Legendre, John Farrar - Geometry - 1825 - 294 pages
...and the solidity of the cylinder will be n R2 x H, or nR*H. LEMMA. •* 520. The convex surface of a **right prism is equal to the perimeter of its base multiplied by its altitude.** Now the altitudes ^F, BG, CH, &c., of these rectangles arc each equal to the altitude of the prism.... | |
| Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - American fiction - 1828 - 598 pages
...multiplied by its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a **right prism, is equal to the perimeter of its base multiplied by its altitude.'** Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number... | |
| Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - American fiction - 1828 - 598 pages
...multiplied by its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a **right prism, is equal to the perimeter of its base multiplied by its altitude.'** Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number... | |
| Adrien Marie Legendre - Geometry - 1836 - 394 pages
...situated, and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a **right prism is equal to the perimeter of its base multiplied by its altitude.** Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF. For,... | |
| Adrien Marie Legendre - Geometry - 1839 - 372 pages
...situated, and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a **right prism is equal to the perimeter of its base multiplied by its** al1iiude. Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF.... | |
| Charles Davies - Geometrical drawing - 1840 - 262 pages
...will the section be similar to the base 1 Of Solids bounded by Planes. 18. The convex surface of a **right prism, is equal to the perimeter of its base, multiplied by** the altitude. Thus, BG (AB+BC+CD+DE+EA) is equal to the convex surface. 19. The convex surface of a... | |
| Adrien Marie Legendre - Geometry - 1841 - 288 pages
...(291), and the solidity of the cylinder will be * W x If, or * IPH. LEMMA. 520. The convex surface of a **right prism is equal to the perimeter of its base multiplied by its altitude.** Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (fig. 252),... | |
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