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The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude.
An Elementary Geometry and Trigonometry - Page 71
by William Frothingham Bradbury - 1872 - 238 pages

## Elements of Geometry

Adrien Marie Legendre - Geometry - 1819 - 574 pages
...(291), and the solidity of the cylinder will be rR*xH, or »/?*//. MMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (j%. 25S),...

## Elements of Geometry and Trigonometry: With Notes

Adrien Marie Legendre - Geometry - 1822 - 394 pages
...solidity of the cylinder will be a-R2 x M, or a-R2 H. PROPOSITION II. LEMMA. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. For this surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c, (see fig. of Def. 5.)...

## Elements of Geometry...: Translated from the French for the Use of the ...

Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...(291), and the solidity of the cylinder will be n R' x H, or nR'H. LEMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Now the altitudes AF, BG, CH, &c., of these rectangles are each equal to the altitude of the prism....

## Elements of Geometry...: Translated from the French for the Use of the ...

Adrien Marie Legendre, John Farrar - Geometry - 1825 - 294 pages
...and the solidity of the cylinder will be n R2 x H, or nR*H. LEMMA. •* 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Now the altitudes ^F, BG, CH, &c., of these rectangles arc each equal to the altitude of the prism....

## The North American Review, Volume 27

Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - American fiction - 1828 - 598 pages
...multiplied by its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a right prism, is equal to the perimeter of its base multiplied by its altitude.' Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number...

## The North American Review, Volume 27

Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - American fiction - 1828 - 598 pages
...multiplied by its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a right prism, is equal to the perimeter of its base multiplied by its altitude.' Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number...

## Elements of Geometry and Trigonometry

Adrien Marie Legendre - Geometry - 1836 - 394 pages
...situated, and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF. For,...

## Elements of Geometry and Trigonometry

Adrien Marie Legendre - Geometry - 1839 - 372 pages
...situated, and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a right prism is equal to the perimeter of its base multiplied by its al1iiude. Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF....