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" The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. "
An Elementary Geometry and Trigonometry - Page 71
by William Frothingham Bradbury - 1872 - 238 pages
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Elements of Geometry

Adrien Marie Legendre - Geometry - 1819 - 574 pages
...(291), and the solidity of the cylinder will be rR*xH, or /?*//. MMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (j%. 25S),...
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Elements of Geometry and Trigonometry: With Notes

Adrien Marie Legendre - Geometry - 1822 - 394 pages
...solidity of the cylinder will be a-R2 x M, or a-R2 H. PROPOSITION II. LEMMA. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. For this surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c, (see fig. of Def. 5.)...
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Elements of Geometry...: Translated from the French for the Use of the ...

Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...(291), and the solidity of the cylinder will be n R' x H, or nR'H. LEMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Now the altitudes AF, BG, CH, &c., of these rectangles are each equal to the altitude of the prism....
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Elements of Geometry...: Translated from the French for the Use of the ...

Adrien Marie Legendre, John Farrar - Geometry - 1825 - 294 pages
...and the solidity of the cylinder will be n R2 x H, or nR*H. LEMMA. •* 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Now the altitudes ^F, BG, CH, &c., of these rectangles arc each equal to the altitude of the prism....
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The North American Review, Volume 27

Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - American fiction - 1828 - 598 pages
...multiplied by its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a right prism, is equal to the perimeter of its base multiplied by its altitude.' Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number...
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The North American Review, Volume 27

Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - American fiction - 1828 - 598 pages
...multiplied by its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a right prism, is equal to the perimeter of its base multiplied by its altitude.' Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number...
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Elements of Geometry and Trigonometry

Adrien Marie Legendre - Geometry - 1836 - 394 pages
...situated, and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF. For,...
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Elements of Geometry and Trigonometry

Adrien Marie Legendre - Geometry - 1839 - 372 pages
...situated, and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a right prism is equal to the perimeter of its base multiplied by its al1iiude. Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF....
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First Lessons in Geometry: With Practical Applications in Mensuration, and ...

Charles Davies - Geometrical drawing - 1840 - 262 pages
...will the section be similar to the base 1 Of Solids bounded by Planes. 18. The convex surface of a right prism, is equal to the perimeter of its base, multiplied by the altitude. Thus, BG (AB+BC+CD+DE+EA) is equal to the convex surface. 19. The convex surface of a...
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Elements of Geometry

Adrien Marie Legendre - Geometry - 1841 - 288 pages
...(291), and the solidity of the cylinder will be * W x If, or * IPH. LEMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (fig. 252),...
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