Given, the first term a, the common difference d, and the number of terms n, to find s, the sum of the series. If we take an arithmetical series, of which the first term is 3, common difference 2, and number of terms 5, it may be written in the following... Elements of Algebra: For Colleges, Schools and Private Students - Page 255by Joseph Ray - 1866 - 406 pagesFull view - About this book
| Joseph Ray - Algebra - 1848 - 250 pages
...feet the next, and so on, how far will it fall the twentieth second? Ans. 627^ feet. ART. 223. — Given, the first term a, the common difference d,...terms n, to find s, the sum of the series. If we take an arithmetical series of which the first term is 3, common difference 2, and number of terms 5, it... | |
| Joseph Ray - Algebra - 1848 - 252 pages
...the next, and so on, how far will it fall the twentieth second? Ans. 627 1 feet. ART. 9S8. — Qiven, the first term a, the common difference d, and the number of terms n, to find .v, the gum of the series. If we take an arithmetical series of which the first term is 3, common difference... | |
| Joseph Ray - Algebra - 1852 - 408 pages
...series is increasing, but subtract it from the first term when the series is decreasing. ART. 393. Having given the first term a, the common difference...inverted order, we have S= 1+3 + 5+ 7+ 9+11, S=ll+9 +7+6+3+1. ' Adding, 28=12+12+12+12+12+12. =12X the number of terms. =12X6=72. Whence, S=£- of 72=36,... | |
| Joseph Ray - Algebra - 1848 - 250 pages
...feet the next, and so on, how far will it fall the twentieth second ? Ans. 627 £ feet. ART. 22 3.— Given, the first term a, the common difference d,...terms n, to find s, the sum of the series. If we take an arithmetical series of which the first term is 3, common difference 2, and number of terms 5, it... | |
| Joseph Ray - Algebra - 1852 - 420 pages
...contains four variable quantities, •ny one of which may be found when the other three are known ART. 293. Having given the first term a, the common difference...in an inverted order, we have S= 1+3 + 5+ 7+ 9+11, 8=11+9 + 7+ 6+ 3+ 1. Adding, 28=12+12+12+12+12+12. 2S=12X the number of terms. 28=12x6=72. Whence,... | |
| Joseph Ray - Algebra - 1866 - 252 pages
...first sec., 48| ft. the next, and so on, how far will it fall the twentieth sec.? Ans. 627^ ft. 223. Given, the first term a, the common difference d,...terms n, to find s, the sum of the series. If we take an arithmetical series, of which the first term is 3, common difference 2, and number of terms 5, it... | |
| Joseph Ray - Algebra - 1866 - 250 pages
...will it fall the twentieth sec.? Ans. 627^ ft. 223. Given, the first term a, the common difference <7, and the number of terms n, to find s, the sum of the series. If we take an arithmetical series, of which the first term is 3, common difference 2, and number of terms 5, it... | |
| Webster Wells - Algebra - 1879 - 468 pages
...preceding term by adding a negative quantity ; consequently the common difference is negative. 368. Given the first term, a, the common difference, d, and the number of terms, n, to find the last term, I. The progression will be a, a + d, a + 2 d, a + 3 d, We observe that these terms differ... | |
| Webster Wells - Algebra - 1880 - 498 pages
...preceding term by adding a negative quantity ; consequently the common difference is negative. 368. G1ven the first term, a, the common difference, d, and the number of terms, n, to find the last term, I. The progression will be a, a + d, a + 2d, a + 3 d, We observe that these terms differ... | |
| Webster Wells - Algebra - 1885 - 370 pages
...0, —3, ...is a decreasing arithmetical progression, in which the common difference is —3. 311. Given the first term, a, the common difference, d, and the number of terms, n, to find the last term, I. The progression is a, a + d, a + 2d, a + 3d, •.. It will be observed that the coefficient... | |
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